Answer:
2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu
Explanation:
The reactants are:
Iron = Fe
Copper (II) sulfate solution = CuSO₄
The reaction is given as:
Fe + CuSO₄ → Fe₂(SO₄)₃ + Cu
This is a single displacement reaction;
Now let us balance the equation;
aFe + bCuSO₄ → cFe₂(SO₄)₃ + dCu
Conserving Fe;
a = 2c
Conserving Cu;
b = d
Conserving S;
b = 3c
Conserving O;
4b = 12c
let b = 1;
c =
d = 1
a =
Multiply through by 3 to get whole numbers;
a = 2, b = 3, c = 1 and d = 3
2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu
Answer:
- 8.5gNaI × 1molNaI/78gNaI × 234.7g AgI / 1 MOL AgI × 2Mol Ag I / 1mol Na2S=51.2 g of AgI reacts with Na2 S
Explanation:
conversion factor is used to make sure that all the units cancels with the other units and we only remain with the mass of Ag I which is 51.2g but since the number of moles can be calculated by dividing with the relative molecular mass therefore 51.2g/234.7gmol=0.22mol
Answer:.25 M
Explanation: .4mol/1.6L = .25 M