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tresset_1 [31]
3 years ago
6

Earth can be called a “spaceship” because it takes up volume in space. Is this true or false? Thanks! :D

Chemistry
2 answers:
zubka84 [21]3 years ago
5 0
It would be false your welcpmd
Evgen [1.6K]3 years ago
4 0
It would be false because earths a planet

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yaroslaw [1]

Answer:

2. True

3. True

4. False

Explanation:

4 0
3 years ago
Do steps 3 as outlined in the lab guide. Record your results in the appropriate blanks
Fittoniya [83]

Answer:

A=  27

B=  16

C=  9

D=  4

E=  2

F=  2

G=  0

H= 0

6 0
3 years ago
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What's the balanced equation for Iron and copper (II) sulfate solution.
Georgia [21]

Answer:

 2Fe +  3CuSO₄  →  Fe₂(SO₄)₃   +  3Cu

Explanation:

The reactants are:

   Iron  = Fe

  Copper (II) sulfate solution = CuSO₄

The reaction is given as:

            Fe +  CuSO₄  →  Fe₂(SO₄)₃   +  Cu

This is a single displacement reaction;

  Now let us balance the equation;

             aFe +  bCuSO₄  →  cFe₂(SO₄)₃   +  dCu

Conserving Fe;

                       a  = 2c

  Conserving  Cu;

                      b  = d

  Conserving S;

                      b  = 3c

  Conserving O;

                    4b  = 12c  

let b  = 1;

    c = \frac{1}{3}  

     d  = 1

     a  = \frac{2}{3}

Multiply through by 3 to get whole numbers;

  a  = 2, b = 3, c  = 1 and d  = 3

           2Fe +  3CuSO₄  →  Fe₂(SO₄)₃   +  3Cu

           

5 0
3 years ago
In the reaction 2AgI + Na2S → Ag2S +2NaI, calculate the number of moles of AgI needed to react with 85.0 g
cluponka [151]

Answer:

  1. 8.5gNaI × 1molNaI/78gNaI × 234.7g AgI / 1 MOL AgI × 2Mol Ag I / 1mol Na2S=51.2 g of AgI reacts with Na2 S

Explanation:

conversion factor is used to make sure that all the units cancels with the other units and we only remain with the mass of Ag I which is 51.2g but since the number of moles can be calculated by dividing with the relative molecular mass therefore 51.2g/234.7gmol=0.22mol

8 0
3 years ago
What is the molarity of 0.40 mol of NaCI dissolved in 1.6 L of solution
Evgesh-ka [11]

Answer:.25 M

Explanation: .4mol/1.6L = .25 M

8 0
3 years ago
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