Answer:
Solid is ur answer
Explanation:
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No they are not, as climate is long term conditions for an area while weather is temporary
Answer : The final temperature of the aluminum and ethylene glycol is ![56.2^oC](https://tex.z-dn.net/?f=56.2%5EoC)
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of aluminum = ![0.900J/g^oC](https://tex.z-dn.net/?f=0.900J%2Fg%5EoC)
= specific heat of ethylene glycol = ![2.36J/g^oC](https://tex.z-dn.net/?f=2.36J%2Fg%5EoC)
= mass of aluminum = 13.60 g
= mass of ethylene glycol = 23.27 g
= final temperature of aluminum and ethylene glycol = ?
= initial temperature of aluminium = ![13.91^oC](https://tex.z-dn.net/?f=13.91%5EoC)
= initial temperature of ethylene glycol = ![65.66^oC](https://tex.z-dn.net/?f=65.66%5EoC)
Now put all the given values in the above formula, we get:
![13.60g\times 0.900J/g^oC\times (T_f-13.91)^oC=-23.27g\times 2.36J/g^oC\times (T_f-65.66)^oC](https://tex.z-dn.net/?f=13.60g%5Ctimes%200.900J%2Fg%5EoC%5Ctimes%20%28T_f-13.91%29%5EoC%3D-23.27g%5Ctimes%202.36J%2Fg%5EoC%5Ctimes%20%28T_f-65.66%29%5EoC)
![T_f=56.2^oC](https://tex.z-dn.net/?f=T_f%3D56.2%5EoC)
Therefore, the final temperature of the aluminum and ethylene glycol is ![56.2^oC](https://tex.z-dn.net/?f=56.2%5EoC)
Ionic bond is the bond that creates a crystalline structure