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3 years ago

Which molecule has a lewis structure that does not obey the octet rule?

1 answer:

5 0

I believe a possible Lewis dot structure that does not obey the octet rule, where all elements are required to have 8 electrons in their outermost shell, would be the SF4 molecule.

Sulfur can contain an more than 8 electrons, in this molecule and thus has an expanded octet.

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A solution is prepared by adding 91.3 g of sodium bromide [NaBr], to 115. g of water. Determine whether the solution is saturate

MrMuchimi

Answer: The given solution is unsaturated solution

Explanation:

We are given:

Solubility of NaBr = 9.19 m

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

A precipitate is defined as the insoluble salt which is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

There are three conditions:

When $m_{\text{(calculated)}}$ ; the solution is unsaturated
When $m_{\text{(calculated)}}=m_{\text{(given)}}$ ; the solution is saturated
When $m_{\text{(calculated)}}>m_{\text{(given)}}$ ; precipitate will form

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (sodium bromide) = 91.3 g

$M_{solute}$ = Molar mass of solute (sodium bromide) = 103 g/mol

$W_{solvent}$ = Mass of solvent (water) = 115 g

Putting values in above equation, we get:

$\text{Calculated molality of NaBr}=\frac{91.3\times 1000}{103\times 115}\\\\\text{Calculated molality of NaBr}=7.71m$

As, the calculated solubility is less than the given solubility. So, the solution will be unsaturated.

Hence, the given solution is unsaturated solution

5 0

3 years ago

What is the pH of 0.166 M triethylammonium chloride, (C2H5)3NHCl. The Kb of triethylamine, (C2H5)3N, is 5.2 x 10-4.?

777dan777 [17]

Answer:

5.7

Explanation:

(C₂H₅)₃NHCl dissociates according to the following equation.

(C₂H₅)₃NHCl ⇒ (C₂H₅)₃NH⁺ + Cl⁻

The molar ratio of (C₂H₅)₃NHCl to (C₂H₅)₃NH⁺ is 1:1. Then, the concentration of (C₂H₅)₃NH⁺ is Ca = 0.166 M.

(C₂H₅)₃NH⁺ is the conjugate acid of (C₂H₅)₃N. Given the Kb of (C₂H₅)₃N, we can calculate Ka for (C₂H₅)₃NH⁺ using the following expression.

Ka × Kb = Kw

Ka = Kw / Kb

Ka = 1.0 × 10⁻¹⁴ / 5.2 × 10⁻⁴

Ka = 1.9 × 10⁻¹¹

(C₂H₅)₃NH⁺ dissociates according to the following equation.

(C₂H₅)₃NH⁺ ⇄ (C₂H₅)₃N + H⁺

We can calculate [H⁺] using the following expression.

[H⁺] = √(Ca × Ka) = √(0.166 × 1.9 × 10⁻¹¹) = 1.8 × 10⁻⁶

The pH is:

pH = -log [H⁺] = -log 1.8 × 10⁻⁶ = 5.7

7 0

3 years ago

Which represents a deletion of a section of the DNA shown here?

luda_lava [24]

The answer for that would be C. this is because it is the only one where a base of the DNA was deleted. A. added another base to it, B. was exactly the same, and D. was a mutation of the DNA because it changed one part of it
Therefore, the answer is C
Hope this helped! :D

8 0

3 years ago

How does an atom become a positively charged ion

sladkih [1.3K]

When, it donates electons.

as for example take
NaCl ( sodium chloride)

it's an ionic compund,
that means it is formed by donating or gaining electrons

Na is writen first than, it must be electropositive i.e it has donated electons which made it positive and the clorine gains electron so it's electronegative.

Na is positive because
as we know it's atomic number is 11 that means it has 11 protons and 11 electrons
now, when it donate electon it has, greater number of protons whose change is +ve so the atom becomes overall positively charged ion or cation.

and something same happens in clorine and because it gains one electron and the number of electrons increase in it by 1 whise charge is -ve so, the atom becomes negatively charged ion or anion which has a -1 charge.

3 0

3 years ago

Defintion of isometry

BARSIC [14]

A transformation that is invariant with respect to distance. That is, the distance between any two points in the pre-image must be the same as the distance between the images of the two points.

8 0

3 years ago