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STatiana [176]
3 years ago
8

Gas in a balloon occupies 3.3 L. What volume will it occupy if the pressure is changed from 100.0 kPa to 90.0 kPa (at constant t

emperature).
Chemistry
1 answer:
german3 years ago
8 0
Since the temperature is a constant, we can use Boyle's law to solve this.<span>

<span>Boyle' law says "at a constant temperature, the pressure of a fixed amount of an ideal gas is inversely proportional to its volume.

P α 1/V               </span>⇒                 PV = k (constant)<span>

Where, P is the pressure of the gas and V is the volume.

<span>Here, we assume that the </span>gas in the balloon is an ideal gas. 

We can use Boyle's law for these two situations as,
            P</span>₁V₁ = P₂V₂<span>

P₁ = 100.0 kPa = 1 x 10⁵ Pa
V₁ = 3.3 L
P₂ = 90.0 x 10³ Pa
V₂ =?

By substitution,
    1 x 10⁵ Pa x 3.3 L = 90 x 10³ Pa x V₂</span><span>
                            V</span>₂ = 3.7 L<span>
</span><span>Hence, the volume of gas when pressure is 90.0 kPa is 3.7 L.</span></span>
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