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STatiana [176]
2 years ago
8

Gas in a balloon occupies 3.3 L. What volume will it occupy if the pressure is changed from 100.0 kPa to 90.0 kPa (at constant t

emperature).
Chemistry
1 answer:
german2 years ago
8 0
Since the temperature is a constant, we can use Boyle's law to solve this.<span>

<span>Boyle' law says "at a constant temperature, the pressure of a fixed amount of an ideal gas is inversely proportional to its volume.

P α 1/V               </span>⇒                 PV = k (constant)<span>

Where, P is the pressure of the gas and V is the volume.

<span>Here, we assume that the </span>gas in the balloon is an ideal gas. 

We can use Boyle's law for these two situations as,
            P</span>₁V₁ = P₂V₂<span>

P₁ = 100.0 kPa = 1 x 10⁵ Pa
V₁ = 3.3 L
P₂ = 90.0 x 10³ Pa
V₂ =?

By substitution,
    1 x 10⁵ Pa x 3.3 L = 90 x 10³ Pa x V₂</span><span>
                            V</span>₂ = 3.7 L<span>
</span><span>Hence, the volume of gas when pressure is 90.0 kPa is 3.7 L.</span></span>
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<span>A dog is trained to sit and shake hands. These traits are most likely?

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3 years ago
The mineral magnesite contains magnesium carbonate, MgCO3 (molar mass= 84 g/mol), and other impurities. When a 1.26-g sample of
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The answer is 33.33 %


The explanation:


According to the reaction equation:


MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)


we can see that 1 mole of MCO3 will produce → 1 mole of CO2


-Now we need o get number of mole of CO2:


and when we have 0.22 g of CO2, so number of mole = mass / molar mass


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∴ mass of Mg = moles * molar mass


= 0.005 * 84 /mol = 0.42 g


∴ Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100


= 33.33 %



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