A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o

Question

3 years ago

12

f 0.235 M H2SO4 will neutralize this solution?

1 answer:

andrew11 [14] · Answer 1 · 2022-03-27T13:31:40+03:00

702 mL of 0.235 M H₂SO₄ solution are needed to neutralize the NaOH

Explanation:

When sodium hydroxide (NaOH) is neutralized by the sulphuric acid (H₂SO₄) the following chemical reaction occur:

2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O

number of moles = mass / molecular weight

number of moles of NaOH = 13.20 / 40 = 0.33 moles

Taking in account the chemical reaction, we devise the following reasoning:

if 2 moles of NaOH are reacting with 1 mole of H₂SO₄

then 0.33 moles of NaOH are reacting with X moles of H₂SO₄

X = (0.33 × 1) / 2 = 0.165 moles of H₂SO₄

molar concentration = number of moles / volume (L)

volume = number of moles / molar concentration

volume of H₂SO₄ solution = 0.165 / 0.235 = 0.702 L = 702 mL

Learn more about:

molar concentration

#learnwithBrainly