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natita [175]
3 years ago
12

A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o

f 0.235 M H2SO4 will neutralize this solution?
Chemistry
1 answer:
andrew11 [14]3 years ago
8 0

702 mL of 0.235 M H₂SO₄ solution are needed to neutralize the NaOH

Explanation:

When sodium hydroxide (NaOH) is neutralized by the sulphuric acid (H₂SO₄) the following chemical reaction occur:

2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O

number of moles = mass / molecular weight

number of moles of NaOH = 13.20 / 40 = 0.33 moles

Taking in account the chemical reaction, we devise the following reasoning:

if        2 moles of NaOH are reacting with 1 mole of H₂SO₄

then   0.33 moles of NaOH are reacting with X moles of H₂SO₄

X = (0.33 × 1) / 2 = 0.165 moles of H₂SO₄

molar concentration = number of moles / volume (L)

volume = number of moles / molar concentration

volume of H₂SO₄ solution = 0.165 / 0.235 = 0.702 L = 702 mL

Learn more about:

molar concentration

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Answer:

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Explanation:

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