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posledela
2 years ago
7

If boron atoms have 5 electrons, how many electrons are in the outer electron shell of a boron atom?

Chemistry
1 answer:
ANEK [815]2 years ago
3 0

Answer:

3

Explanation:

The first election shell can only hold 2 electrons, but the next one can hold up to 8

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Which of the following is an inorganic compound?<br> AgNO3<br> C6H12<br> СНОН<br> C₂H7N
Lemur [1.5K]

Answer:

AgNO3

Explanation:

Silver nitrate (AgNO3) is an inorganic compound. Organic compounds usually have 1+ C.

4 0
3 years ago
A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed
AlekseyPX

(a) 4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 20.68N_2;

(b) 4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2;

(c) 23 900 kg air; (d) air:fuel = 10.2; (e) air:fuel = 12.2:1

(a) <em>Balanced equation including N_2 from air</em>  

The balanced equation <em>ignoring</em> N_2 from air is  

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2  

Moles of N_2 =55 mol O_2 × (3.76 mol N_2/1 mol O_2) = 206.8 mol N_2  

<em>Including</em> N_2 from air, the balanced equation is  

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 206.8N_2  

(b) <em>Balanced equation for 120 % stoichiometric combustion</em>  

Moles of O_2 = 55 mol O_2 × 1.20 = 66.00 mol O_2  

Excess moles O_2 = (66.00 – 55) mol O_2 = 11.00 mol O_2  

Moles of N_2 = 66.00 mol O_2 × (3.76 mol N_2/1 mol O_2) = 248.2 mol N_2  

The balanced equation is

4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2

(c) <em>Minimum mass of air</em>  

Moles of O_2 required = 1700 kg C_11 H_7S

× (1 kmol C_11 H_7S/185.24 kg C_11 H_7S) × (55 kmol O_2/4 kmol C_11 H_7S)

= 126.2 kmol O_2  

Mass of O_2 = 126.2 kmol O_2 × (32.00 kg O_2/1 kmol O_2) = 4038 kg O_2  

Mass of N_2 required = 126.2 kmol O_2 × (3.76 kmol N_2/1 kmol O_2)

× (28.01 kg N_2/1 kmol N_2) = 13 285 kg N_2  

Mass of air = Mass of N_2 + mass of O_2 = (4038 + 13 285) kg = 17 300 kg air  

(d) <em>Air:fuel mass ratio for 100 % combustion</em>  

Air:fuel = 17 300 kg/1700 kg = <em>10.2 :1 </em>

(e) <em>Air:fuel mass ratio for 120 % combustion </em>

Mass of air = 17 300 kg × 1.20 = 20 760 kg air  

Air:fuel = 20 760 kg/1700 kg = 12.2 :1  

6 0
2 years ago
Characteristic of enzymes allows it to be highly specific in the reactions they catalyze?
Lana71 [14]
The way that an enzyme forms from a polypeptide bond and the bonds formed between it caracterise the enzymes active site 

the active site is specific to certain substrates which are catalysed 
hope that helps <span />
6 0
3 years ago
Read 2 more answers
During a hot and humid day, large and dense clouds known as cumulonimbus clouds form. In many cases these clouds will result in
julsineya [31]

the answer is c- thunderstorms                                                        

5 0
3 years ago
How many protons, electrons and neutrons are in the isotope 13C ?
Vadim26 [7]

Hey there!

We can tell from the information we are given that the sum of protons and neutrons is 13, there is 6 protons since it is a carbon atom, and there is no charge which means the number of protons is equal to the number of electrons.

6 + n = 13

n = 7

The number of protons is equal to the number of electrons, so there is 6 electrons.

The isotope 13C has 6 protons, 6 electrons, and 7 neutrons.

Hope this helps!

7 0
2 years ago
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