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Luda [366]
3 years ago
12

What is necessary for a metallic bond to form?

Chemistry
2 answers:
Vedmedyk [2.9K]3 years ago
8 0
C thats the answer yes
Sonbull [250]3 years ago
8 0

Answer:

i think the answer is b the atoms should be far apart

Explanation:

You might be interested in
44.2124+0.81+7.335 significant digits
zhenek [66]

52  

Explanation:

We need to understand and apply the rules of significant figures when carrying out addition operations to solve this problem:

Rules of significant figures:

  • Non-zero digits are always significant in a given number
  • Any zeros between two significant digits are significant.
  • A final zero or trailing zeros in the decimal portion is significant.
  • Any leading zero in a decimal is significant.

In addition, the answer of the sum is given to the least number of significant digits of the given numbers:

 

        44.2124

    +    0.81

    +    7.335

sum  52.3574          

Now the least number of significant figure is 2 as seen in 0.81

we round the sum up to 52  

learn more:

Significant numbers brainly.com/question/6384538

#learnwithBrainly

4 0
3 years ago
When a bond is formed, energy is _________ the environment.
zepelin [54]
When a bond is formed, energy is released into the environment. That is because it is an exothermic reaction, it releases energy. <span />
8 0
3 years ago
Read 2 more answers
One hundredth of a meter is called a
Lena [83]
That is called one centimeter
5 0
4 years ago
Alice and Marge are studying the properties of matter. The girls cut some silver-colored magnesium sheets into 3-inch long strip
frosja888 [35]
<span>B) Magnesium reacts in acids</span>
4 0
3 years ago
Read 2 more answers
Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
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