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True [87]
3 years ago
8

Are compounds considered pure substances?

Chemistry
1 answer:
Naya [18.7K]3 years ago
6 0
A compound<span> is a </span>pure substance<span> composed of two or more different atoms chemically bonded to one another. A </span>compound<span> can be destroyed by chemical means. It might be broken down into simpler </span>compounds<span>, into its elements or a combination of the two.</span>
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carbon-carbon covalent bonds, such as the ones in carbohydrates and lipids, are _____ and have _____.
NARA [144]

Answer:

Weak; a lot of potential energy.

Explanation:

6 0
3 years ago
How many moles of sodium atoms are contained in 3.5 moles of sodium sulfide
Aliun [14]

Answer:

7 moles

Explanation:

The molecular formula of sodium sulfide is Na_2S

One molecule of Sodium sulfide has 2 atoms of sodium and one atom of sulfur

1 mole of Sodium sulfide has  2 moles of sodium and one mole of sulfur

so 3.5 moles of sodium sulfide will have 2× 3.5 moles of sodium atoms

i.e 2×3.5= 7 moles of sodium atom

7 0
4 years ago
7. Write a balanced chemical equation for the following reactions and label what type of reaction it is. (3 points)
slamgirl [31]
(A) Naoh + Hno3 == Nano3 + h20.
and it is acid based reaction.
(B) H + Br == Hbr. it is synthesis reaction
and it should be hydrogen gas with bromine gas if that was question then
H2 + Br2 == 2Hbr
(c) 3Agno3 + Alcl3 == Al (No3)3 + 3Agcl
it is double displacement. and we right the polyatomic ion in bracket that’s why no3 is in bracket.
please let me know if you need something
5 0
3 years ago
Read 2 more answers
El agua salubre es aquella que tiene más sales disueltas que el agua dulce. En el análisis de una muestra de aguas se encontró q
Slav-nsk [51]

Answer:

0.39 % m/m; 0.42 % m/v; 0.18 % v/v; 4200 ppm; 0.044 mol·L⁻¹; 0.041 mol/kg;

0.089 equiv/L; 0.000 74; 0.999 26

Explanation

Data:

Mass  of MgCl₂       =       3.8   g

Volume of solution =  900      mL

Density of solution =       1.09 g/mL

Density of MgCl₂    =      2.32 g/cm³

Calculations

1. Percent m/m

\text{Mass percent} = \dfrac{\text{Mass of component}}{\text{Total mass}} \times 100 \, \%\\\\\text{Total mass} = \text{900 mL} \times \dfrac{\text{1.09 g}}{\text{1 mL}} = \text{981 g}\\\\\text{Mass percent} = \dfrac{\text{3.8 g}}{\text{981 g}} \times 100 \,\% = \textbf{0.39 \% m/m}

2. Percent m/v

\text{Mass-by-volume percent} = \dfrac{\text{Mass of component}}{\text{Total volume}} \times 100 \, \%\\\\\text{ Mass-by-volume percent } = \dfrac{\text{3.8 g}}{\text{900 mL}} \times 100 \,\% = \textbf{0.42 \% m/v}

3. Percent v/v

\text{Volume percent} = \dfrac{\text{Volume of component}}{\text{Total volume}} \times 100 \, \%\\\\\text{Volume of MgCl}_{2} = \text{3.8 g} \times \dfrac{\text{1 mL}}{\text{2.32 g}} = \text{1.64 mL}\\\\\text{ Mass-by-volume percent } = \dfrac{\text{1.64 mL}}{\text{900 mL}} \times 100 \,\% = \textbf{0.18 \% v/v}

4. Parts per million

\text{Ppm} = \dfrac{\text{milligrams of solute}}{\text{litres of solution}} = \dfrac{\text{3800 mg}}{\text{0.900 L}} = \textbf{ 4200 ppm}

5. Molar concentration

\text{Molar concentration} = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\\text{Moles of MgCl}_{2} = \text{3.8 g} \times \dfrac{\text{1 mol}}{\text{95.21 g}} = \text{0.040 mol}\\\\\text{Molar concentration} = \dfrac{\text{0.040 mol}}{\text{0.900 L}} = \textbf{0.044 mol/L}

6. Molal concentration

\text{Molal concentration} = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}

Mass of water = Mass of solution - mass of solute = 981 g - 3.8 g = 977 g = 0.977 kg

\text{Molar concentration} = \dfrac{\text{0.040 mol}}{\text{0.977 kg}} = \textbf{0.041 mol/kg}

7. Normality

The normality is the number of equivalents per litre of solution.

The normality of an ion equals the molar concentration times the charge on the ion.

Thus, the normality of MgCl₂ is twice the molar concentration.

Normality = 2 × 0.044 mol·L⁻¹ = 0.089 equiv·L⁻¹

8. Mole fraction of solute

\chi_{\text{solute}} = \dfrac{n_{\text{solute}}}{n_{\text{total}}}

Moles of MgCl₂ = 0.040 mol

\text{Moles of water} = \text{977 g} \times \dfrac{\text{1 mol}}{\text{18.02 g}} = \text{54.23 mol}

Total moles = n₂ + n₁ = 0.040 mol + 54.23 mol = 54.27 mol

\chi_{2} = \dfrac{\text{0.040 mol}}{\text{54.23 mol}} = \mathbf{0.00074}

9. Mole fraction of solvent

χ₁ = 1 - χ₂ = 1 - 0.000 74 = 0.999 26

4 0
3 years ago
The polar nature of water molecules gives water many unique properties. Which of these statements is NOT true regarding the prop
inessss [21]

B) Water only dissolves other non-polar molecules.

<em>This option is wrong because water is a polar molecule and it can dissolve only other polar molecules.</em>

6 0
4 years ago
Read 2 more answers
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