Ask question

Ask question

All categories

2 years ago

5

What is the volume, in liters, of 2.00 moles of hydrogen at STP?

1 answer:

Ber [7]2 years ago

8 0

The volume of one mole of any gas at STP is 22.4 L. So, at STP, the volume of 2.00 moles of hydrogen gas would be (22.4 L/mol)(2 mol H2) = 44.8 L.

You might be interested in

What is the rule for determining the mass of an atom

Elena-2011 [213]

Answer:

For any given isotope, the sum of the numbers of protons and neutrons in the nucleus is called the mass number. This is because each proton and each neutron weigh one atomic mass unit. By adding together the number of protons and neutrons and multiplying by 1, you can calculate the mass of the atom.

5 0

2 years ago

dentify the correct formula for the following ionic compounds. - sodium chloride - magnesium chloride - calcium oxide - lithium

andrey2020 [161]

Explanation:

The chemical formula of an ionic compound can be written by using the symbols of the respective cations and anions.

The overall charge on the molecule should be zero.

Hence, the total charge of cations=total charge of anions.

The symbols of the given molecules are shown below:

sodium chloride ---- NaCl

magnesium chloride --- $MgCl_2$

calcium oxide ---- CaO

lithium phosphide---- $Li_3P$

aluminum sulfide ----- $Al_2S_3$

calcium nitride---- $Ca_3N_2$

5 0

2 years ago

Determine the frequency of light with a wavelength of 2.672 x 10^-7cm

yaroslaw [1]

Answer:

Determine the frequency of light with a wavelength of 2.775⋅10−7 cm. Answer in units of Hz?❤

8 0

1 year ago

Which statement explains the process of a chemical reaction? A. Substances are mixed together, producing a homogeneous mixture.

ololo11 [35]

The answer is D: Products combine to produce new reactants... Hope this helps! :)

3 0

2 years ago

Read 2 more answers

Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ

inessss [21]

Answer:

$\Delta S^{0}$ for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: $\frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)$

$\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]$

where $S^{0}$ represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

$\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K$

So, $\Delta S^{0}$ for the given reaction is -99.4 J/K

7 0

3 years ago