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kherson [118]
3 years ago
5

What is the volume, in liters, of 2.00 moles of hydrogen at STP?

Chemistry
1 answer:
Ber [7]3 years ago
8 0
The volume of one mole of any gas at STP is 22.4 L. So, at STP, the volume of 2.00 moles of hydrogen gas would be (22.4 L/mol)(2 mol H2) = 44.8 L.
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Draw the Lewis dot structure for RbIO2. Include all hydrogen atoms and nonbonding electrons. Show the formal charges of all atom
Rzqust [24]

Answer : The Lewis-dot structure of RbIO_2  is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, RbIO_2

As we know that rubidium has '1' valence electrons, iodine has '7' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in RbIO_2 = 1 + 7 + 2(6) = 20

As we know that RbIO_2  is an ionic compound because it is formed by the transfer of electron takes place from metal to non-metal element.

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3 years ago
Describe the flow of blood to the human body, including through each of the four chambers of the heart. Explain how the blood ch
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3 years ago
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This is a material that transmits most of the light that strikes to pass through and only a small amount of light is reflected o
inn [45]

Answer:

Optically Transparent

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3 years ago
What is the force of attraction between covalently bonds molecules
serg [7]
The bound state implies a net attractive force between<span> the atoms.</span><span> </span>bond<span> in which one or more electrons from one atom are removed and attached to another atom, resulting in positive and negative ions which attract each other. hope it helps 

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6 0
4 years ago
If 12.8 g lead(II) sulfate (303.3 g/mol) precipitates when excess potassium chloride is added to 1.65 L of a water sample, what
quester [9]

Answer:

M=0.0256M

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

PbSO_4(aq)+2KCl(aq)\rightarrow PbCl_2(s)+K_2SO_4(aq)

In such a way, since all the lead (II) is converted due to the excess of potassium chloride, the moles of lead (II) in the sample are computed from the mass of lead (II) sulfate:

n_{Pb^{2+}}=12.8gPbSO_4*\frac{1molPbSO_4}{303.3gPbSO_4} *\frac{1molPb^{2+}}{1molPbSO_4} \\\\n_{Pb^{2+}}=0.0422molPb^{2+}

Thus, since volume of the solution is 1.65 due to the fact that the addition of the reactants is not enough to significantly modify the reaction's volume, the resulting molar concentration of the lead (II) ions is:

M=\frac{n_{Pb^{2+}}}{V}=\frac{0.0422molPb^{2+}}{1.65L}\\  \\M=0.0256M

Regards.

5 0
4 years ago
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