Answer:
the car to the right
Explanation:
its in the name the RIGHT of way hope it helps good luck
Answer:
![h_{max} = 51.8 cm](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%2051.8%20cm)
Explanation:
given data:
height of tank = 60cm
diameter of tank =40cm
accelration = 4 m/s2
suppose x- axis - direction of motion
z -axis - vertical direction
= water surface angle with horizontal surface
accelration in x direction
accelration in z direction
slope in xz plane is
![tan\theta = \frac{a_x}{g +a_z}](https://tex.z-dn.net/?f=%20tan%5Ctheta%20%3D%20%5Cfrac%7Ba_x%7D%7Bg%20%2Ba_z%7D)
![tan\theta = \frac{4}{9.81+0}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7B4%7D%7B9.81%2B0%7D)
![tan\theta =0.4077](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D0.4077)
the maximum height of water surface at mid of inclination is
![\Delta h = \frac{d}{2} tan\theta](https://tex.z-dn.net/?f=%5CDelta%20h%20%3D%20%5Cfrac%7Bd%7D%7B2%7D%20tan%5Ctheta)
![=\frac{0.4}{2}0.4077](https://tex.z-dn.net/?f=%20%3D%5Cfrac%7B0.4%7D%7B2%7D0.4077)
![\Delta h 0.082 cm](https://tex.z-dn.net/?f=%20%5CDelta%20h%20%200.082%20cm)
the maximu height of wwater to avoid spilling is
![h_{max} = h_{tank} -\Delta h](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%20h_%7Btank%7D%20-%5CDelta%20h)
= 60 - 8.2
![h_{max} = 51.8 cm](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%2051.8%20cm)
the height requird if no spill water is ![h_{max} = 51.8 cm](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%2051.8%20cm)
Answer:
<u><em>note:</em></u>
<u><em>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</em></u>
Answer:
diesel fuel is pumped at high pressure to the injectors which are responsible for entering the fuel into the combustion chamber,
when the piston is at the top the pressure is so high that it explodes the fuel (diesel) that results in a generation of mechanical power
Answer:
The final velocity of the rocket is 450 m/s.
Explanation:
Given;
initial velocity of the rocket, u = 0
constant upward acceleration of the rocket, a = 18 m/s²
time of motion of the rocket, t = 25 s
The final velocity of the rocket is calculated with the following kinematic equation;
v = u + at
where;
v is the final velocity of the rocket after 25 s
Substitute the given values in the equation above;
v = 0 + 18 x 25
v = 450 m/s
Therefore, the final velocity of the rocket is 450 m/s.