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3 years ago

A) What is the peak value of the voltage?

Physics

1 answer:

GrogVix [38]3 years ago

8 0

Answer:

Check answer in below explanation

Explanation:

Peak value:

It is the maximum value which is attained by alternating voltage. It is also known as crest value. It is represented by Vm.

Equation of alternating voltage is

V=Vm Sinωt;

Where Vm is the Peak value of voltage

RMS value:

It is the square mean root of instantaneous value of voltage.It is represented by Vrms.

Vrms is given by

Vrms= $\sqrt{\frac{1}{T} \int\limits^T_0 {V^2} \, dt}$ ;

Vrms= $\sqrt{\frac{1}{T} \int\limits^T_0 {Vm^2*sin^2wt} \, dt}$ ;

Finallly,

Vrms=Vm/(√2);

Angular frequency for this voltage signal:

It describe how the fast object is moving.It is represented by ω.and ω is

Given by ω=2*π*f;

Where f is simple frequency.

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Answer:

4.2 km

Explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as isosceles triangle, scalene triangle, equilateral triangle and right angled triangle.

Sine rule states that for a triangle with angles A,B and C and corresponding opposite sides a, b, and c, the following formula holds:

$\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}$

Let the starting point be A, hence the side opposite to the angle = a = distance travelled in north east direction.

Let the point of 60° of northeast be B = 90° + (90° - 60°) = 120°, hence the side opposite to the angle = b = resultant displacement = 8 km.

Let C be the endpoint, hence the side opposite to the angle = c = distance travelled north = 5 km

Using sine rule:

$\frac{b}{sin(B)}=\frac{c}{sin(C)} \\\\\frac{8}{sin(120)}=\frac{5}{sin(C)} \\\\sin(C)=\frac{5*sin(120)}{8} =0.5412\\\\C=sin^{-1}(0.5412)=32.8^o\\\\$

∠A + ∠B + ∠C = 180° (sum of angle in a triangle)

∠A + 120 + 32.8 = 180

∠A = 27.2°

$\frac{b}{sin(B)}=\frac{a}{sin(A)} \\\\\frac{8}{sin(120)}=\frac{a}{sin(27.2)} \\\\a=\frac{8*sin(27.2)}{sin(120)} \\\\a=4.2\ km$

Therefore she travelled 4.2 km in the north east direction

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A light beam in glass (n = 1.5) reaches an air-glass interface, at an angle of 60 degrees from the surface. What is the angle of

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Answer:

θ₂ = 35.26°

Explanation:

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