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victus00 [196]
3 years ago
8

True or False along a divergent boundary, two plates slip past each other,moving in opposite directions.

Physics
1 answer:
kiruha [24]3 years ago
7 0
False....................................
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SOH-CAH-TOA is used to solve for the ________
Misha Larkins [42]

Answer:

c. initial (x and y)

Explanation:

When a projectile is launched at a velocity with a launch angle, to solve it, we must first resolve the initial velocity into the x and y components. To do this will mean we have to treat it like a triangle due to the launch angle and the direction of the projectile.

Therefore, we will have to make use of trigonometric ratios which is also known by the mnemonic "SOH CAH TOA"

Thus, this method resolves the initial x and y velocities.

3 0
3 years ago
A mechanic pushes a 2.60 ✕ 103-kg car from rest to a speed of v, doing 5,430 J of work in the process. During this time, the car
Oduvanchick [21]

Part A. We are given that a car is pushed from rest to a final speed doing 5430 Joules of work. -

To determine the final velocity we will use the work and energy theorem which states that the work done is equal to the change in kinetic energy:

W=K_f-K_0

Since the car starts from rest this means that the initial kinetic energy is zero:

W=K_f

The kinetic energy is given by:

K=\frac{1}{2}mv^2

Substituting in the formula we get:

W=\frac{1}{2}mv_f^2

Now, we solve for the final velocity. First, we multiply both sides by 2 and divide both sides by the mass:

\frac{2W}{m}=v_f^2

Now, we take the square root to both sides:

\sqrt{\frac{2W}{m}}=v_f

Now, we plug in the values:

\sqrt{\frac{2(5430J)}{2.6\times10^3kg}}=v_f

Solving the operations:

2.04\frac{m}{s}=v_f

Therefore, the final velocity is 2.04 m/s.

Part B. Now, we use the following formula for work:

W=Fd

Where "F" is the force and "d" is the distance.

Now, we set this equation equal to the work done by the force:

Fd=5430J

Now, we divide both sides by the distance "d":

F=\frac{5430J}{29m}=187.2N

Therefore, the force exerted is 187.2 Newton.

7 0
2 years ago
Why do scientists not use US customary units when reporting their data?
Marianna [84]
From britaññica it said time and money. They didn’t have either to switch over from the industrial period and never did. Also from my own person reasoning i think most of the world uses not US customary, so to make stuff more accessible. hope this helps!
8 0
3 years ago
what do you mean by momentum? avehicle is runing with a velocity of 5m/s. it the momentum of the vehicle is 5000kg m/s. what is
Fantom [35]
Momentum is simply a quantity that measures the impact of a moving body over something is due to the mass it posseses or the velocity with which it is moving. Mathematically,ut is the product of mass and velocity of a body. It is represented by capital p...(P) P=mv Solution to the problem: we know P=mv For mass,eliminate m from the equation, m=P/v Put values, m=5000/5=1000kg
8 0
3 years ago
An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing
exis [7]

Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane =  7.2 × 10³ kg

density of air =  1.29 kg/m³

using Bernoulli's equation

 P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2

 \Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)

 \Delta P =9977.5 Pa

Applying newtons second law

2 Δ P x A - mg = 0

A =\dfrac{mg}{2\Delta P}

A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}

    A = 3.53 m²

7 0
3 years ago
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