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Llana [10]
3 years ago
9

Neptune is 30 AU (astronomical units) from the sun. How long, in light minutes, would it take for light from the sun to reach Ne

ptune?
Chemistry
1 answer:
shtirl [24]3 years ago
7 0

Answer:

250 light minutes takes

Explanation:

1 astonomical unit is equal to 1.50x10¹¹m

The light travels at the speed of 3.0x10⁸m/s. That means in 1 second, travels 3.0x10⁸m. To solve this question we must find the distance of neptune to the sun in meters. In this way we can find the seconds (And minutes) that need the light to travel from the sun to neptune:

<em>Distance from Sun to neptune:</em>

30AU * (1.50x10¹¹m / 1AU) = 4.5x10¹²m

<em>Time transcurred:</em>

4.5x10¹²m * (1s / 3.0x10⁸m) = 15000s

15000s * (1min / 60s) =

<h3>250 light minutes takes</h3>

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Calculate the vapor pressure at 25°C of a solution containing 55.3 g ethylene glycol (HOCH2CH2OH) and 285.2 g water. The vapor p
Snezhnost [94]

Answer:

Vapor pressure of solution = 23.9 Torr

Explanation:

Let's apply the colligative poperty of vapor pressure to solve this:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

We have solvent and solute mass, so let's find out the moles of each.

55.3 g / 62 g/mol = 0.89 moles

285.2 g / 18 g/mol = 15.84 moles

Let's determine the mole fraction of ethylene glycol.

Mole fraction = Moles of ethylene glyco / Total moles

0.89 moles / (0.89 + 15.84) = 0.053

25.3 Torr - Vapor pressure of solution = 25.3 Torr . 0.053

Vapor pressure of solution = 25.3 Torr . 0.053 - 25.3 Torr

Vapor pressure of solution = 23.9 Torr

7 0
3 years ago
Read 2 more answers
Please help with this question
tamaranim1 [39]
1.806x10^24
Written equation form(always start the equation off with what you know based off of the question!):

3mol(CCl4)•6.022x10^23/1mol = 1.806x10^24

Good luck!
3 0
3 years ago
How can you distinguish a clastic sedimentary rock from a crystalline formed sedimentary rock?
Ket [755]
:<span>  </span><span>A clastic sedimentary rock will be full of... clasts. Pieces of shells, ooids, pizoids, etc. A chemically formed sedimentary rock may have these but it will dominantly be a layered rock, you should be able to see concentric layers</span>
6 0
3 years ago
Of the following substances, only _____ has London dispersion forces as its only intermolecular force.
Aleksandr [31]

Answer:

A

Explanation:

a) C6H14, C8H18 – London-dispersion force

Since both substances have the same intermolecular force, the substances with the

larger molecular mass with have the higher boiling point. In this case, C8H18 will

have the higher boiling point.

b) C3H8 – London-dispersion force

CH3OCH3 –Dipole-dipole

The higher boiling point belongs to CH3OCH3 because is has the stronger

intermolecular force, dipole-dipole interaction.

c) CH3OH – Hydrogen bonding

CH3SH – Dipole-dipole interaction

Hydrogen bonding is the strongest intermolecular force, so CH3OH will have the

higher boiling point.

d) NH2NH2 – Hydrogen bonding

CH3CH3 – London-dispersion force

Hydrogen bonding is the strongest intermolecular force, so NH2NH2 will have the

higher boiling point.

5 0
3 years ago
0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is:
sashaice [31]

Answer:

Option c. 1.10 moles

Explanation:

By the moles of the two reactants, we need to determine the limiting reactant.

If we only have the mass (or the moles) of one, we assume the other is in excess.

The reaction is: 2Al(OH)₃(s) + 3H₂SO₄(aq)  → Al₂(SO₄)₃(aq) + 6H₂O(l)

Let's work with stoichiometry: 2 moles of hidroxide react with 3 moles of sulfuric acid.

Then, 0.450 moles of hidroxide, will react with (0.450 . 3) / 2 = 0.675 moles of acid. Notice we have 0.550 of it, so we do not have enough acid to react, therefore the H₂SO₄ is the limiting reagent

Let's do another rule of three. Ratio is 3:6

3 moles of acid can produce 6 moles of water

Then, 0.550 moles of acid, will produce (0.550 . 6) / 3 = 1.1 moles of water

8 0
3 years ago
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