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algol13
3 years ago
7

A car moves along a horizontal road with constant velocity v0 = v0xi until it encounters a smooth inclined hill, which it climbs

with constant velocity v1 = v1xi + v1yj as indicated in the figure. The period of time during which the car changes its velocity is Δt.
Physics
1 answer:
Serga [27]3 years ago
8 0

Answer:

a ave = ( v1x - v0x ) i/Δt  + v1y j/Δt

Explanation:

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Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

T^2 \propto R^3

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

T^2 \propto R^3

T^2 = kR^3

Substituting the values, we get the value of constant k for mars.

687^2 = k\times (2.279 \times 10^{11})^3

k = 3.92 \times 10^{-29}

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

365^3 = 3.92\times 10^{-29} R^3

R^3 = 3.39 \times 10^{33}

R= 1.50 \times 10^{11}\;\rm m

Hence we can conclude that the distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

6 0
3 years ago
Carbon has 4 valence electrons. Hydrogen has 1 valence
geniusboy [140]

Answer:

4 hydrogen atoms can form chemical bond with 1 carbon atom.

Explanation:

CH4. methane

7 0
3 years ago
Light shines through a single slit whose width is 5.7 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a
lilavasa [31]

Answer:

\lambda = 570\ nm

Explanation:

Given,

Width of slit, W = 5.7 x 10⁻⁴ m

Distance between central bright fringe, L = 4 m

distance between central bright fringe and first dark fringe, y = 4 mm

Diffraction angle

tan \theta = \dfrac{y}{L}

tan \theta = \dfrac{4}{4\times 10^3}

\theta = 0.0572

Now.

W sin \theta = m \lambda

m = 1

5.7 \times 10^{-4} \times sin (0.0572) = 1 \times \lambda

\lambda = 569.99 \times 10^{-9}\ m

\lambda = 570\ nm

4 0
3 years ago
What’s the purpose of life?
Alborosie
Purpose of life is to explore and get experience. Another reason is to love and let what makes you happy guide you
5 0
4 years ago
A 6.0-kg ball is sliding to the right at 25.0m/s and strikes a second ball (15-kg) that is initially at rest head-on. After the
katrin [286]

Answer:

15 m/s to the right

Explanation:

Let's say right is positive and left is negative.

Momentum is conserved:

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(6.0 kg) (25.0 m/s) + (15 kg) (0 m/s) = (6.0 kg) (-12.5 m/s) + (15 kg) v₂

v₂ = 15 m/s

5 0
3 years ago
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