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quester [9]
4 years ago
10

Which atom is involed in giving your heart energy to beat​

Physics
1 answer:
VladimirAG [237]4 years ago
5 0

Answer:

I think the answer the this question that you asked is pulse?

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The velocity of an object is the _____ of the object
katovenus [111]
D. Speed and direction, this is because velocity is a vector quantity so has a magnitude and direction assigned to it because it is the rate of change of displacement.
6 0
3 years ago
Jack bought 8 boxes of soda. how many cans did he buy if each box holds 34 cans?
Alenkasestr [34]

Answer:

272

Explanation:

hope this helps you!!!

4 0
4 years ago
Describe the energy transfers of an electron around a circuit when the switch is closed
motikmotik

Answer:

When a switch is closed, electrons move through a circuit from the negative side of a battery to the positive side

Explanation:

Note that current is marked to flow from positive to negative on circuit diagrams, but that's for historical reasons only. Benjamin Franklin did a fabulous job of understanding what was going on, but no one yet knew about protons & electrons, so he assumed current was flowing from positive to negative.

However, what really happens is electrons flow from negative (where they repel each other) to positive (where they are attracted).

As electrons flow through a circuit, they need 'something to do'. In many cases, that something is to light a bulb or heat an element, such as an element on a stove. So, the energy of an electron can be converted to heat or light.

I hope I'm understanding your question correctly

6 0
3 years ago
A circular wire loop of radius LaTeX: RR lies in the xy-plane with the z-axis running through its center. There is initially no
frosja888 [35]

Answer:

Explanation:

Given a circular loop of radius R

r = R

Note: the radius lies in the xy plane

Area is given as

A = πr² = πR²

At t = 0, no magnetic field B=0

The magnetic field is given as a function of time

B = C•exp(t) •i + D•t² •k

Where C and D are constant

We want to find the magnitude of EMF in the circular loop.

EMF is given as

ε = - N•dΦ/dt

Where,

N is number of turn and in this case we will assume N = 1.

Φ is magnetic flux and it is given as

Φ = BA

ε = - N•d(BA)/dt

Where A is a constant, then we have

ε = - N•A•dB/dt

B = C•exp(t) •i + D•t² •k

dB/dt = C•exp(t) •i + 2D•t •k

Then,

ε = - N•A•dB/dt

ε = - 1•πR²•(C•exp(t) •i + 2D•t •k)

ε = -πR²•(C•exp(t) •i + 2D•t •k)

So, let find the magnitude of EMF

Generally finding magnitude of two vectors R = a•i + b•j

Then, |R| = √a² + b²

So, applying this we have,

ε = πR² (√(C²•exp(2t) + 4D²t²))

From the given magnetic field, we are given that,

B = 0 at t = 0

B = C•exp(t) •i + D•t² •k

B = 0 = C•exp(0) •i + D•0² •k

0 = C

Then, C = 0.

So, substituting this into the EMF.

ε = πR² (√(0²•exp(2t) + 4D²t²))

ε = πR² (√4D²t²)

ε = πR² × 2Dt

ε = 2πDR²t

So, the EMF is also a function of time

ε = 2πDR²t

4 0
4 years ago
g A wave pulse on a light string encounters a boundary with a heavy string. In other words, the pulse moves from a medium with a
sammy [17]

Answer:

The answer to the question is

Changing travel medium from one of low density to another of higher density (heavier weight) reduces the speed of the transmitted pulse

Explanation:

The rate of propagation of a wave in a medium is correlated to the properties of the medium. in  a guitar, sound is produced by vibrating the string. The frequency of the produced sound depends on the speed and wavelength of the wave as follows

v = f × λ

The guitar strings, though having equal length, the produce sounds of different frequencies and they also have different linear mass density.

As highlighted, the speed of sound is a function function of the frequency and the frequency produced in a string is related to the linear density

The relation between speed with linear density of a material, or its mass per unit length is

v absolute  = \sqrt{\frac{F_{T} }{\mu} } where

v absolute = The absolute velocity

F_{T} = The horizontal tension on the string

\mu = Mass per unit length of the string = \frac{m}{l} where

m = Mass of the string and

l = Length  of the measured mass of string

There fore the wave propagates more slowly, or slows down when it changes its travel medium from one of lower linear mass density to a different medium having a higher density

The speed of the transmitted pulse reduces in the heavier string

8 0
3 years ago
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