Answer:
F. 0J
Explanation:
At the objects highest point in the trajectory the KE = 0 since this trajectory is completely vertical with no x-component but its PE would be greatest at this point.
KE = (1/2)mv²
KE = 0; because velocity equals 0
PE = m*g*h
PE = 1kg*(9.81m/s^2)*10m
PE = 98.1J
Answer:
The energy stored is 1.4 x 10^-9 J.
Explanation:
Side of square, L = 10 cm = 0.1 m
Distance, d = 2 mm = 0.002 m
Electric field, E = 4000 V/m
The energy stored in the capacitor is
The capacitance is given by
If we are talking on the force being exerted by a segment of a rope of lenght R on the right on a point M which is being also pulled from the Left by a segment of rope R as shown in the figure attached. Then we invoke Newton's Third Law:
"Any force exerted by an object (in this case a segment of the rope) also suffers a equal and opposite force".
If we pick
whis is the tension exerted by the right segment then the left segment will also exert an equal and opposite force so we have that
KE = 1/2mv²
= 1/2(20 kg)(2m/s²)
= 1/2(20)(4)
= 1/2 (80)
KE = 40 J
hope this helps :)