The area of the effort and load of the Piston of a hydrolic are 0.5 and 5m respectively. If a force of 100 Newton is applied on
the effort piston determine the first safety of the load. Solve
1 answer:
Answer:
Explanation:
Using Pascal laws, which states that pressure are the input equals the pressure at the output.
Pressure is given as force/area
P1=P2
Then,
F1/A1=F2/A2
Cross multiply
F1A2=F2A1
Given that
Ae=0.5m² area of effort
Al=5m² area of load
Fl=? Force if load
Fe= 100N. Force of effort
Then applying pascal
Fl/Al=Fe/Ae
Fl/5=100/0.5
FL/5=200
Fl=200×5
Fl=1000N
The first safety load is 1000N
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Answer:
2.3 Nm clockwise
Explanation:
Take counterclockwise to be positive and clockwise to be negative.
∑τ = (3 N) (2.5 m) − (7 N) (1.4 m)
∑τ = 7.5 Nm − 9.8 Nm
∑τ = -2.3 Nm
The net torque is 2.3 Nm clockwise.
Answer: It's the third one.
Explanation:
Answer:
2000metres
Explanation:
Pressure= density x height x gravity
Gravity is always a constant = 10N/kg
so height= Pressure/( density x gravity)
h= 20000000/(1000 x10)
h= 2000 metres
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