The area of the effort and load of the Piston of a hydrolic are 0.5 and 5m respectively. If a force of 100 Newton is applied on
the effort piston determine the first safety of the load. Solve
1 answer:
Answer:
Explanation:
Using Pascal laws, which states that pressure are the input equals the pressure at the output.
Pressure is given as force/area
P1=P2
Then,
F1/A1=F2/A2
Cross multiply
F1A2=F2A1
Given that
Ae=0.5m² area of effort
Al=5m² area of load
Fl=? Force if load
Fe= 100N. Force of effort
Then applying pascal
Fl/Al=Fe/Ae
Fl/5=100/0.5
FL/5=200
Fl=200×5
Fl=1000N
The first safety load is 1000N
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