The area of the effort and load of the Piston of a hydrolic are 0.5 and 5m respectively. If a force of 100 Newton is applied on
1 answer:
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The centripetal acceleration is
Explanation:
For an object in uniform circular motion, the centripetal acceleration is given by
where
v is the speed of the object
r is the radius of the circle
The speed of the object is equal to the ratio between the length of the circumference () and the period of revolution (T), so it can be rewritten as
Therefore we can rewrite the acceleration as
For the particle in this problem,
r = 2.06 cm = 0.0206 m
While it makes 4 revolutions each second, so the period is
Substituting into the equation, we find the acceleration:
Learn more about centripetal acceleration:
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To solve this problem it is necessary to use the concepts related to Snell's law.
Snell's law establishes that reflection is subject to
Where,
Angle between the normal surface at the point of contact
n = Indices of refraction for corresponding media
The total internal reflection would then be given by
Therefore the would be equal to
Therefore the largest value of the angle α is 30.27°