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Usimov [2.4K]
3 years ago
6

Which of the following solutions would have the lowest freezing point?

Chemistry
1 answer:
Paul [167]3 years ago
4 0

B. 3.0 mol·L⁻¹ NaCl

Explanation:

Freezing point is a colligative property: it depends only on the number of particles in solution.

The for freezing point depression ΔT_f is

ΔT_f = iK_fb

where

i = the number of moles of particles available from one mole of solute

K_f = the molal freezing point depression constant

b = the molal concentration of the solute

All your solutions are aqueous NaCl. They differ only in their concentrations.

Thus, the most concentrated solution will have the greatest freezing point depression and the lowest freezing point.

Read more on Brainly.com - brainly.com/question/11516173#readmore

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A freighter ship carrying a cargo of uranium hexafluoride sank in the English Channel in late August 1984. The cargo of uranium
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Answer:

Heyo (Ish Mash Potato) XD

Explanation:

a freighter carrying a cargo of uranium hexafluoride sank in the english channel in 1984. the cargo of uranium hexafluoride weighed 2.25x10 to the eight power. kg and was contained in 30 drums, each having a volume of 1.62x10 to the sixth power L. what is the density in g/ml, of uranium hexafloride.

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3 years ago
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A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of
Bad White [126]

Answer:

a) T_{2} = 360.955\,K, P_{2} = 138569.171\,Pa\,(1.386\,bar), b) T_{2} =  347.348\,K, V_{2} = 0.14\,m^{3}

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{v}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{v}}

The number of moles of the ideal gas is:

n = \frac{P_{1}\cdot V_{1}}{R_{u}\cdot T_{1}}

n = \frac{\left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}} \right)\cdot (0.12\,m^{3})}{(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} )\cdot (298\,K)}

n = 5.541\,mol

The final temperature is:

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}

T_{2} = 360.955\,K

The final pressure is:

P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}

P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)

P_{2} = 138569.171\,Pa\,(1.386\,bar)

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}

T_{2} =  347.348\,K

The final volume is:

V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}

V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})

V_{2} = 0.14\,m^{3}

4 0
3 years ago
Revolver features several firing chambers located within...
Blizzard [7]

Answer:

What are the characteristics of a revolver?

Explanation:

The revolver features several firing chambers located within a revolving cylinder. The cylinder rotates as the revolver is fired, lining up each bullet mechanically.

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2 years ago
A cylinder is labeled \"PENTANE.\" When the gas inside the cylinder is monochlorinated, five isomers of formula C5H11Cl result.
melisa1 [442]

Answer:

a mixture of two these

Explanation:

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n-pentane has three different kinds of equivalent hydrogen atoms leading to three isomeric monochlorides formed.

Isopentane has four different types of equivalent hydrogen atoms hence four isomeric monochlorides are formed.

Lastly, neopentane has only one type of equivalent hydrogen atoms that yields one mono chlorination product.

Hence the cylinder must contain a mixture of isopentane and neopentane which yields four and one isomeric monochlorides giving a total of five identifiable monochloride products as stated in the question.  

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What makes a strong acid different from a weak acid?
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Answer:

Strong acids react faster where as weak acids take time to react with any base.

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