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yawa3891 [41]
2 years ago
7

Billy pushes 15.0 kg block at a rate of 2.5 m/s/s eastward. What is the net force Billy applied to the block?

Physics
2 answers:
vekshin12 years ago
8 0

Answer:

,mjmhgjk,mnhbfgtyhyiuhyglufkcvlbvkch

Explanation:

sladkih [1.3K]2 years ago
5 0
I believe the answer would be 37.5

Since F=ma plug the numbers

F=15*2.5

15*2.5=37.5
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A 70 kg student stands on top of a 5.0 m platform diving board . how much gravitational potential energy does the student have?
Marianna [84]

Answer:

a. P.E = 3430Joules.

b. Workdone = 3430Nm

Explanation:

<u>Given the following data;</u>

Mass = 70kg

Distance = 5m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the potential energy;

Potential energy = mgh

P.E = 70*9.8*5

<em>P.E = 3430J</em>

b. To find the workdone;

Workdone = force * distance

But force = mass * acceleration

Force = 70*9.8

Force = 686 Newton.

Workdone = 686 * 5

<em>Workdone = 3430Nm</em>

6 0
2 years ago
When practicing an oral presentation what can you do to prepare for the presentation
Igoryamba
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8 0
3 years ago
PLEASE HELP!!! I have so much work left to do. PLEASE!!!
Neko [114]

Answer:

the answer is C.

Explanation:

6 0
3 years ago
What is the electric potential energy of a charge that experiences a force of 3.6 x 10^-4N when it is 9.8 x 10^-5 from the sourc
Levart [38]
The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:
U=qV
The potential is given by the magnitude of the electric field, E, times the distance, d:
V=Ed
So we have
U=qEd (1)
However, the electric field is equal to the electrical force F divided by the charge q:
E= \frac{F}{q}
Therefore (1) becomes
U=Fd
And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
U=Fd=(3.6 \cdot 10^{-4}N)(9.8 \cdot 10^{-5} m)=3.53 \cdot 10^{-8} J
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3 years ago
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vladimir1956 [14]
The answer is D. disorganized
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