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yawa3891 [41]
3 years ago
7

Billy pushes 15.0 kg block at a rate of 2.5 m/s/s eastward. What is the net force Billy applied to the block?

Physics
2 answers:
vekshin13 years ago
8 0

Answer:

,mjmhgjk,mnhbfgtyhyiuhyglufkcvlbvkch

Explanation:

sladkih [1.3K]3 years ago
5 0
I believe the answer would be 37.5

Since F=ma plug the numbers

F=15*2.5

15*2.5=37.5
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During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
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Answer:

The force is F = 1041.7N

Explanation:

The moment of Inertia I is mathematically evaluated as

               I = MR_A^2

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                      \tau = FR_B  - F_rR_A

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                     \tau = F (0.0435) - 135 (0.33)

This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of \alpha  = 3.70 rad/s^2 and this torque can also be represented mathematically as

                   \tau = \alpha I

Now equating the two equation for torque

                                F (0.0435) - 135 (0.33) = \alpha I    

Making F the subject

                     F = \frac{\alpha I + (135*0.33) }{0.0435}

Substituting values

                  F = \frac{(3.70 * 0.207)  + (135*0.33)}{0.0435}

                       = 1041.7N

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