<h2>Question: </h2>
The nearpoint of an eye is 151 cm. A corrective lens is to be used to allow this eye to clearly focus on objects 25 cm in front of it. What should be the focal length of this lens?
Answer:
29.96cm
Explanation:
Using the corrective lens, the image should be formed at the front of the eye and be upright and virtual.
Now using the lens equation as follows;
-------------(i)
Where;
f = focal length of the lens
v = image distance as seen by the lens
u = object distance from the lens
From the question;
v = -151cm [-ve since the image formed is virtual]
u = 25cm
Rewrite equation (i) to have;
Substitute the values of v and u into the equation;
f = 29.96cm
The focal length should be 29.96cm
The number of waves arriving at the same place in a fixed amount
of time is directly related to the frequency of the waves.
Answer:
C
Explanation:
During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom.
A conglomerate is a rock that forms as a result of compaction
and cementation. The correct answer between all the choices given
is the first choice or letter A. I am hoping that this answer has satisfied
your query and it will be able to help you in your endeavor, and if you would
like, feel free to ask another question.
Answer:
fundamental formula for density = Kg/m³
Explanation:
density = mass/volume
