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vlada-n [284]
3 years ago
5

Help with 5-10 please

Physics
1 answer:
Zina [86]3 years ago
5 0

Answer:

explained in attachment

Explanation:

explained in attachment

Download pdf
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A mass of 10 g of oxygen fill a weighted piston–cylinder device at 20 kPa and 110°C. The device is now cooled until the tempe
mezya [45]

Answer:

The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

Explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

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Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

\Delta V=V_{2}-V_{1}

\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})

Put the value into the formula

\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)

\Delta V=14.297\ L

\Delta V=14.3\times10^{-3}\ m^3

Hence, The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

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<h3>Question 1</h3>

Answer

option C) velocity

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<h3>Question 3</h3>

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Four aqueous solutions and their concentrations are shown in the above illustration. which of the solutions is most likely to be
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