Answer:
4086 J
Explanation:
The potential energy is transformed to kinetic energy less the frictional energy. Potential energy= mgh where m represent mass, g is acceleration due to gravity and h is the height of cliff
Since we have force of air resistance, work done due to air resistance will be product of force and distance
Substituting 10 Kg for m, 9.81 for g and 60 m for F then the kinetic energy at the bottom will be
KE= 10*9.81*60- (30*60)=4086 J
Answer: Given:
Initial velocity= 36km/h=36x5/18=10m/s
Final velocity =54km/h=54x5/18=15m/s
Time =10sec
Acceleration = v-u/ t
=15-10/10=5/10=1/2=0.5 m/s2
Distance =s=?
From second equation of motion:
S=ut +1/2 at^2
=10*10+1/2*0.5*10*10
=100+25
=125m
So distance travelled 125m
Hope it helps you
Gravitational potential energy<span> is </span>energy<span> an object possesses because of its position in a </span>gravitational<span> field. </span><span>The equation for </span>gravitational potential energy<span> is GPE = mgh.
GPE = 1200(1.6)(350) = 672000 J
Hope this answers the question. Have a nice day.</span>
I think its all four of them could be wrong but try all four !!!!!!
Answer:
<em>13.54 tons</em>
Explanation:
Let f be the amount of fuel oxidizer needed
v be the speed
The relationship between them is inverse in nature i.e
f ∝ 1/v
f = k/v
If a rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of 3.25 metric tons to a speed of 10,000 m/s, then f = 3.25 when v = 10,000
Substitute and get k
k = fv
k = 3.25 * 10,000
k = 32500
To get the amount of fuel oxidizer required to produce a speed of 2400m/s, we will find f when v = 2400m/s
Recall that f = k/v
f = 32500/2400
f = 13.54 metric tons
<em>Hence the fuel plus oxidizer that will be required is 13.54 tons</em>
