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3 years ago

Help with 5-10 please

Physics

1 answer:

Zina [86]3 years ago

5 0

Answer:

explained in attachment

Explanation:

explained in attachment

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What is the importance of discovering gravitational waves in science?

S_A_V [24]

<span>The importance of discovering gravitational waves are; one, we can measure the activity between two bodies in orbit in the universe, two, scientist can estimate the merging of two bodies in the universe every 15 minutes by using LIGO and three, we can know the behavior of other bodies that we did not know exist.</span>

4 0

3 years ago

you stand on a straight desert road at night and observe a vehicle approaching. this vehicle is equipped with two small headligh

inysia [295]

Answer:

The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km

Explanation:

Given:

d = distance = 0.679 m

λ = wavelength of the light = 537 nm = 537x10⁻⁹m

dp = pupil diameter = 4.81 mm = 0.00481 m

Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?

For the separation of the peak from the central maximum it is:

$sin\theta =\frac{\lambda }{d_{p} } =\frac{537x10^{-9} }{0.00481} =1.116x10^{-4}$

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

$d_{x} =\frac{d}{sin\theta } =\frac{0.679}{1.116x10^{-4} } =6.084x10^{3} m=6.084km$

7 0

4 years ago

If you increase the frequency of a sound wave four times, what will happen to its speed?

ozzi

The speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

<h3>How to calculate the frequency of a wave.</h3>

Mathematically, the frequency of a sound wave is given by this formula:

$F = \frac{V}{\lambda}$

<u>Where:</u>

F is the frequency of a sound wave.

V is the velocity of a sound wave.

$\lambda$ is the wavelength of a sound wave.

<u>Note:</u> The frequency of the sound wave is increased four (4) times.

F = 4F

Substituting the given parameters into the formula, we have;

$4F = \frac{V}{\lambda}\\\\V=4F\lambda$

Therefore, the speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

Read more on sound wave here: brainly.com/question/19250621

4 0

3 years ago

When a fixed amount of ideal gas goes through thermal expansion what happens to internal energy

Keith_Richards [23]

Answer:

A) its internal (thermal) energy does not change.

Explanation:

When a fixed amount of ideal gas goes through an isothermal expansion

3 0

3 years ago

A proton initially moves left to right along the x-axis at a speed of 2.00 x 103 m/s. It moves into an uniform electric field, w

FinnZ [79.3K]

Answer:

E = 1.04*10⁻¹ N/C

Explanation:

Assuming no other forces acting on the proton than the electric field, as this is uniform, we can calculate the acceleration of the proton, with the following kinematic equation:

$vf^{2} -vo^{2} = 2*a*x$

As the proton is coming at rest after travelling 0.200 m to the right, vf = 0, and x = 0.200 m.

Replacing this values in the equation above, we can solve for a, as follows:

$a = \frac{vo^{2}*mp}{2*x} = \frac{(2.00e3m/s)^{2}}{2*0.2m} = 1e7 m/s2$

According to Newton´s 2nd Law, and applying the definition of an electric field, we can say the following:

F = mp*a = q*E

For a proton, we have the following values:

mp = 1.67*10⁻²⁷ kg

q = e = 1.6*10⁻¹⁹ C

So, we can solve for E (in magnitude) , as follows:

$E = \frac{mp*a}{e} =\frac{1.67e-27kg*1e7m/s2}{1.6e-19C} = 1.04e-1 N/C$

⇒ E = 1.04*10⁻¹ N/C

5 0

3 years ago