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Bas_tet [7]
3 years ago
8

What color is the auroras in the upper nitrogen

Chemistry
1 answer:
Andrej [43]3 years ago
3 0

Just so you know oxygen that is 60 miles up gives off a yellow-green color, but oxygen at higher altitudes about 200 miles above us gives the all red auroras. Ionic Nitrogen produces the blue light and neutral Nitrogen gives off the red-purple and the rippled edges.

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Describe the energy of the products in comparison to the energy the atoms had when the were wandering around the room free.
Over [174]

Answer: The atoms of the solid products are tightly packed whereas those in gas are loose.

Explanation:

Atoms in the solid structure are linked to each other by strong force of attraction and they collectively form an three-dimensional structure. The binding of the atoms form the shape of the solid product. The gas exhibit free atoms in it. The atoms are not linked to one another by strong force of attraction. The atoms as a part of gas have higher energy as those present in the solid products. So, the atoms of the gas wander freely as compared to those in the solid products.

7 0
3 years ago
The rate constant for a certain reaction is k = 4.70×10−3 s−1 . If the initial reactant concentration was 0.700 M, what will the
Lynna [10]

Answer:

Therefore the concentration of the reactant after 4.00 minutes will be 0.686M.

Explanation:

The unit of k is s⁻¹.

The order of the reaction = first order.

First order reaction: A first order reaction is  a reaction in which the rate of reaction depends only the value of the concentration of the reactant.

-\frac{d[A]}{dt} =kt

[A] = the concentration of the reactant at time t

k= rate constant

t= time

Here k= 4.70×10⁻³ s⁻¹

t= 4.00

[A₀] = initial concentration of reactant = 0.700 M

-\frac{d[A]}{dt} =kt

\Rightarrow -\frac{d[A]}{[A]}=kdt

Integrating both sides

\Rightarrow\int -\frac{d[A]}{[A]}=\int kdt

⇒ -ln[A] = kt +c

When t=0 , [A] =[A₀]

-ln[A₀]  = k.0 + c

⇒c= -ln[A₀]  

Therefore

-ln[A] = kt - ln[A₀]

Putting the value of k, [A₀] and t

- ln[A] =4.70×10⁻³×4 -ln (0.70)

⇒-ln[A]=  0.375

⇒[A] = 0.686

Therefore the concentration of the reactant after 4.00 minutes will be 0.686M.

5 0
3 years ago
If 9 moles of P203 are formed, how many<br> moles of O2 reacted?
masha68 [24]
9 x 3 = 27
27 moles of O reacted
27 / 2 = 13.5 O2 reacted
round up to 14 moles of O2
3 0
2 years ago
Is silicon a compound yes or no​
Crazy boy [7]

Answer: Yes

Explanation: Silicon is never found as a free element naturally, meaning it always occurs with other elements.

4 0
3 years ago
in this trial, 0.400 M NaOH was added to 40.00 ml of 0.400 M HCl. How many ml of base must be added to cause the colour to chang
denis-greek [22]

Answer:

The amount of Ml that is needed

6 0
3 years ago
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