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3 years ago

HELP WILL GIVE BRAINLIEST

Physics

1 answer:

RideAnS [48]3 years ago

7 0

Answer:

Reindeer

Explanation:

High traction to walk on ice

Woolly fur to keep warm

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Calculate the mass of earth

Roman55 [17]

Answer:

$m=6.85\times 10^{24}\ kg$

Explanation:

The radius of Earth is $6.67\times 10^6\ m$

The density of an object is given by :

$d=\dfrac{m}{V}$

The density of Erth is, d = 5515 kg/m³

Where

m is the mass of the Earth

So,

$m=d\times V\\\\m=\dfrac{4}{3}\pi r^3\times d$

Put all the values,

$m=\dfrac{4}{3}\pi \times (6.67\times 10^6)^3\times 5515 \\\\m=6.85\times 10^{24}\ kg$

So, the mass of the Earth is equal to $6.85\times 10^{24}\ kg$ .

6 0

3 years ago

An arrow is fired directly horizontal off a cliff that is 10.0 meters tall with a velocity of 65.5m/s how long is the arrow in t

AlladinOne [14]

This would be the correct the answer to the following question above.:
Δy=−10=−gt22

7 0

3 years ago

The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magni

Marina CMI [18]

Answer:

Q = - 256 X 10⁻⁷ C .

Explanation:

Electric field due to a charge Q at a distance d from the center is given by the expression

E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² = $\frac{9\times10^9\times Q}{(14+2)^2\times10^{-4}}$

Q = $\frac{9\times16^2\times10^{-2}}{9\times10^9}$

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

5 0

3 years ago

I NEED HELP ASAP

Levart [38]

Answer:

ig d. transmits only green light.....

8 0

1 year ago

A large ant is standing on the middle of a circus tightrope that is stretched with tension T_s. The rope has mass per unit lengt

k0ka [10]

Answer:

$A = \frac{g \lambda^2 \mu}{4\pi^2 T_s}$

Explanation:

As we know that the speed of the wave in string is given as

$v = \sqrt{\frac{T_s}{\mu}}$

now we will have

frequency of the wave is given as

$f = \frac{v}{\lambda}$

$f = \frac{1}{\lambda}\sqrt{\frac{T_s}{\mu}}$

now if the ant will feel weightlessness then we will have

$mg = m\omega^2 A$

so we will have

$A = \frac{g}{\omega^2}$

$A = \frac{g}{4\pi^2 f^2}$

$A = \frac{g \lambda^2 \mu}{4\pi^2 T_s}$

3 0

4 years ago