Answer:
a = 50.26 rad/s^2
Explanation:
We know that:
θ = 
where θ is the angle, a the angular aceleration and t the time.
First, we need to find how many rad are equivalent to 4 rev, as:
θ = 4 rev * 2π = 25.13 rad
Finally, replacing θ by 25.13 rad and t by 1 second, we get:
25.13 rad = 
Solving for a:
a = 50.26 rad/s^2
Explanation:
Angular momentum is conserved.
I₁ ω₁ = I₂ ω₂
(½ Mr² + md²) ω₁ = (½ Mr²) ω₂
(½ (35 kg) (2.3 m)² + (84 kg) (2.3 m)²) (0.28 rev/s) = (½ (35 kg) (2.3 m)²) ω
ω = 1.624 rev/s
ω = 10.2 rad/s
Round as needed.
There are many skills that scientists don't use to learn about the world.
These skills include playing the harmonica, riding a unicycle, and asking
others to choose from a list and then not telling them what's on the list.
Let u = initial vertical velocity.
Assume that
g = 9.81 m/s²,
Wind resistance is ignored.
When t = 0.220 s, the height is h = 0.537 m. Therefore
0.537 m = (u m/s)*(0.220 s) - (1/2)*(9.81 m/s²)*(0.220 s)²
0.537 = 0.22u - 0.2372
u = 3.519 m/s
The upward velocity after 0.220 s is
v = 3.519 - 9.81*0.22 = 1.363 m/s
At maximum height, the upward velocity is zero. The maximum height, H, is given by
(3.519 m/s)² - 2*(9.81 m/s²)*(H m) = 0
12.3834 - 19.6H = 0
H = 0.632 m
It goes higher by 0.632 - 0.537 = 0.095 m
Answers:
(a) The initial speed is 3.519 m/s.
(b) The speed at 0.537 m height is 1.363 m/s.
(c) It goes higher by 0.095 m.
Answer:
Photosynthesis
Light energy from the sun stimulates photosynthesis by green plants. One major component of the carbon cycle is the reduction of the carbon (IV) oxide content in the atmosphere by plants. Plants take in Carbon (IV) oxide to use during the process of making their own food. During this process light energy is absorbed by chlorophyll and is used to convert carbon (IV) oxide and water to glucose.
This glucose is used during respiration by living organisms that give out carbon (IV) oxide. The cycle continues.
