The formula for the torque is
<span>τf = p F
where
</span><span>τf is the torque
p is the distance where the force is applied by the tendon
F is force applied by the tendon
If there are given values, substitute in the equation and solve for the torque.</span>
Impulse is the change in momentum
J = 1.5 kg(22 m/s - 15 m/s) = 10.5 kg-m/s
As we know that electric field at any point caused due to a point charge given by, kQ/r^2
Where, k is dielectric constant of medium, Q is the point charge and r is the distance between the point charge and point where electric field is to be measured.
Let us assume a charge of q is placed at x=+20cm to make electric field at
x=+10cm zero.
Total electric field at x=+10cm can be shown by equation,
(k X 2.20 X 10^-12)/(10-0)^2 + (k X -4.80 X 10^-12)/(10-(-11))^2 + (k X
q)/(10-20)^2 = 0
=> 2.20 X 10^-14 - 1.09 X 10^-14 + q X 10^-2 = 0
=> q = 1.09 X 10^-12 - 2.20 X 10^-12
=> q = -1.1 X 10^-12 Coulombs or -1.1 pC
Answer:
Explanation:
Angular velocity of satellite
= 2π x .01
= .02 π rad /s
Initial angular momentum
Moment of inertia x angular velocity
= 2000 x .02 π
= 125.6 unit
Linear impulse produced by each thruster
= 15 N.s
Angular impulse
= 15 x 1.5 = 22.5 unit
Total angular impulse in 30 pulses
= 22.5 x 2 x 30
1350
This angular impulse will add total angular momentum of
1350 unit
So total angular momentum after 30 pulses
= 1350 + 22.5
= 1372.5 unit
So final angular velocity
= final angular momentum / moment of inertia
= 1372.5 / 2000
= 0 .686 rad /s
49 J is the total kinetic energy. If a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s. Kinetic energy is the energy an bowling ball has because of its motion.
Given: m = 7.3 Kg ; r = 9.4 cm = 0.094 m ; v = 3.1 m
Now total kinetic energy in this case is given by KE = Kinetic energy due to rotation + Kinetic energy due to translation
i,e KE = 1/2*m*v2 + 1/2*I*ω2 where I is the moment of inertia of the bowling ball about it's center and ω is the angular velocity
Now for pure rotation (without slipping) v = rω
also for the ball (solid sphere) I = 2/5*m*r2
Hence our kinetic energy becomes
KE = 1/2*m*v2 + 1/5*m*v2 = 7/10*m*v2
so KE = 0.7*7.3*(3.1)2 = 49.10 J = 49 J
Learn more about kinetic energy here
brainly.com/question/12669551
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