1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Musya8 [376]
3 years ago
15

Develop an algebraic relationship that describes a satellite moving in a circular orbit around a planet if the speed of the sate

llite is v, the mass of the planet is M, the mass of the satellite is m, the radius of the planet is R, and the altitude of the orbit is h. (You may include the appropriate constants as needed.) Assume that the frictional force is negligible. What will eventually happen to the satellite if the frictional (drag) force is not negligible? What could be done to compensate for a non-negligible drag force that would allow the satellite to maintain its orbit?
Physics
1 answer:
lana [24]3 years ago
5 0

Answer:

Explanation:

For this problem we must use Newton's second law where force is gravitational attraction

      F = m a

Since movement is circular, acceleration is centripetal.

      a = v2 / r

Let's replace

      G m M / r² = m v² / r

      G M r = v²

The distance r is from the center of the planet

      r = R + h

      v = √ GM / (R + h)

If the friction force is not negligible

      F - fr = m a

Where the friction force must have some functional relationship, for example

           Fr = b v + c v² +…

Suppose we are high enough for the linear term to derive the force of friction

          G m M / r - (m b v + m c v2) = m v2

          G M / r - b v = v²

We see that the solution of the problem gives lower speeds and that change over time.

To compensate for this friction force, the motors should be intermittently suspended to recover speed.

You might be interested in
Can someone help me answer this??
Bingel [31]

Answer:

<h2>3,2 oky na dekh Lena ek bar</h2><h2>2,5</h2>
7 0
2 years ago
A young child cannot understand<br>another person's perspective because he is​
natima [27]

Answer:

egocentric

Explanation:

6 0
3 years ago
Which statement is true about the reaction shown by this chemical equation?
KatRina [158]

Answer:

it's C endothermic

Explanation:

5 0
2 years ago
What is the mass of an object travelling at 25 m/s with a kinetic energy of 3775 J?
Arte-miy333 [17]

Answer:

<h2>You can do 6516-3775=2741</h2><h2 /><h2>The difference is 27141 kilometers</h2><h2 /><h2>Did this help?</h2><h2>⇒  Yes or No?</h2>
4 0
2 years ago
A driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch, and then resumes driving for the next 2.0 h through a di
Oksi-84 [34.3K]
<h2>82.353 km/hr</h2>

Explanation:

       The driver travels 135 km towards East in 1.5 hr. He stops for 45 min. He again travels 215 km towards East in 2.0 hr.

       The total displacement of the driver in the given time is ths sum of individual displacements, because all the displacements are in the same directon.

       Total displacement = 135\text{ }km\text{ }East\text{ }+\text{ }0\text{ }km\text{ }+\text{ }215\text{ }km\text{ }East\text{ }=\text{ }350\text{ }km\text{ }East

       Total time travelled = 1.5\text{ }hr\text{ }+\text{ }45\text{ }min\text{ }+\text{ }2.0\text{ }hr\text{ }=\text{ }90\text{ }min\text{ }+\text{ }45\text{ }min\text{ }+\text{ }120\text{ }min\text{ }=\text{ }255\text{ }min\text{ }=\text{ }4\text{ }hr\text{ }15\text{ }min\text{ }=\text{ }4.25\text{ }hr

      \text{Average velocity = }\dfrac{\text{Total displacement}}{\text{Total time taken}}=\dfrac{350\text{ }km}{4.25\text{ }hr}=82.353\text{ }\frac{km}{hr}

∴ Driver's average velocity = 82.353\text{ }\frac{km}{hr}

3 0
3 years ago
Other questions:
  • Give one example in which both physical and chemical changes takes places ​
    6·2 answers
  • How many places are there for electrons in the innermost shell of an atom?
    14·1 answer
  • List the copositional layers in order of most dense to least dense
    11·1 answer
  • Which statement best summarizes the central idea of "Applications of Newton's Law
    10·2 answers
  • A car moving at a speed of 20m/s has a kinetic energy of 300,000 J. What is the car’s mass?
    8·1 answer
  • Which is bigger, a kilometer or a mile?
    7·2 answers
  • after a cannonball is fired into frictionless space, the amount of force needed to keep it going equals​
    10·1 answer
  • What is the power of a juice machine that draws 0.18 amps of current and has a resistance of 75 ohms
    7·1 answer
  • A bowling ball hits two standing bowling pins at the same time. Which of the following is true? Assume that all collisions are e
    5·1 answer
  • ¿por qué los buzos, cuando emergen con urgencia, deben exhalar continuamente durante el ascenso?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!