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Musya8 [376]
3 years ago
15

Develop an algebraic relationship that describes a satellite moving in a circular orbit around a planet if the speed of the sate

llite is v, the mass of the planet is M, the mass of the satellite is m, the radius of the planet is R, and the altitude of the orbit is h. (You may include the appropriate constants as needed.) Assume that the frictional force is negligible. What will eventually happen to the satellite if the frictional (drag) force is not negligible? What could be done to compensate for a non-negligible drag force that would allow the satellite to maintain its orbit?
Physics
1 answer:
lana [24]3 years ago
5 0

Answer:

Explanation:

For this problem we must use Newton's second law where force is gravitational attraction

      F = m a

Since movement is circular, acceleration is centripetal.

      a = v2 / r

Let's replace

      G m M / r² = m v² / r

      G M r = v²

The distance r is from the center of the planet

      r = R + h

      v = √ GM / (R + h)

If the friction force is not negligible

      F - fr = m a

Where the friction force must have some functional relationship, for example

           Fr = b v + c v² +…

Suppose we are high enough for the linear term to derive the force of friction

          G m M / r - (m b v + m c v2) = m v2

          G M / r - b v = v²

We see that the solution of the problem gives lower speeds and that change over time.

To compensate for this friction force, the motors should be intermittently suspended to recover speed.

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Answer:

Option (C)

Explanation:

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It is highly effective, cost-effective and there is no emission of greenhouse gases.

But it also has some disadvantages, of which one is that it produces radioactive waste materials, which are difficult to dispose these substances and is also a very expensive method. These materials emit radiations that are harmful to the organisms. So, it is very challenging to dispose these radioactive waste materials.

Thus, the correct answer is option (C).

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What is the principal of moment​
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Answer:

hope it helps...

Explanation:

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A high school physics student is sitting in a seat read-
Nataly_w [17]

The equilibrium condition allows finding the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Newton's second law gives the relationship between force, mass and acceleration of bodies, in the special case that the acceleration is is zero equilibrium condition.

            ∑ F = 0

Where F is the external force.

The free body diagram is a diagram of the forces on bodies without the details of the shape of the body, in the attached we can see a diagram of the forces.

Let's analyze the force on the chair.

            N_{chair} - W_{chair} - W_{student} = 0 \\ \\N_{chair} = W_{chair} + W_{student}

Let's analyze the forces on the student.

          N_{student} - W_{student} = 0  \\N_{student} = W _{student}

           

In conclusion using the equilibrium condition we can find the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Learn more here: brainly.com/question/18117041

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