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2 years ago

The end of Earth’s_______ that is tilted toward the Sun receives more energy from the Sun?

1 answer:

7 0

Answer: Whichever hemisphere (the Northern or Southern Hemisphere) is tilted toward the sun receives more direct rays of sunlight (or rays that are closer to perpendicular or a 90° angle). The hemisphere tilted toward the sun also has more hours of daylight than the hemisphere that is tilted away from the sun.

Explanation:

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A soccer player kicks a 0.44 kg ball with a force of 57.6 N, what is the ball’s acceleration

noname [10]

THE BALL'S ACCELERATION IS 130.90 $\frac{m}{s}$

Explanation:

According to Newton's second law "the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)", meaning that when the soccer player kicks a ball, a force is acting on the ball, therefore increasing it's acceleration

SO FOR CALCULATING THIS WE WILL USE NEWTON LAW,

FORCE = MASS × ACCELERATION

WE ARE GIVEN

FORCE = 57.6N

MASS= .44KG

SO HERE WE APPLYING FORMULA ,WE WILL GET

ACCELERATION = $\frac{FORCE}{MASS}$

ACCELERATION = $\frac{57.6N}{.44KG}$

ACCELERATION =130.90 $\frac{m}{s}$

8 0

3 years ago

The position of a full moon is located

marissa [1.9K]

Answer:

opposite the sun. between the Earth and the sun. rising perpendicular to the sun.

Explanation:

4 0

3 years ago

Read 2 more answers

The action of two forces. One is a forward force of 1157 N provided by traction between the wheels and the road. The other is a

Pie

Complete question

A 2700 kg car accelerates from rest under the action of two forces. one is a forward force of 1157 newtons provided by traction between the wheels and the road. the other is a 902 newton resistive force due to various frictional forces. how far must the car travel for its speed to reach 3.6 meters per second? answer in units of meters.

Answer:

The car must travel 68.94 meters.

Explanation:

First, we are going to find the acceleration of the car using Newton's second Law:

$\sum\overrightarrow{F}=m\overrightarrow{a}$ (1)

with m the mass , a the acceleration and $\sum\overrightarrow{F}$ the net force forces that is:

$(F-f)$ (2)

with F the force provided by traction and f the resistive force:

(2) on (1):

$(F-f)=ma$

solving for a:

$a=\frac{F-f}{m} =\frac{1157N-902N}{2700kg} =0.094\frac{m}{s^{2}}$

Now let's use the Galileo’s kinematic equation

$Vf^{2}=Vo^{2}+2a\varDelta x$ (3)

With Vo te initial velocity that's zero because it started from rest, Vf the final velocity (3.6) and $\varDelta x$ the time took to achieve that velocity, solving (3) for $\varDelta x$ :