Answer:
d) 2.12 V
Explanation:
E =E° - RT/nF log 1/H⁺ x HSO₄⁻
E = 2.08 - ( .059/2 X log 1/4.5x4.5 )
2.08 - (-0.038 ) = 2.118 =2.12 V
You have learned your lesson well, Suhay. Your statement is correct.
The light rays from the fish BEND when they flow out of the water into the air. But our primitive brain still believes that the light rays flow STRAIGHT from the fish. The result is that the fish does not APPEAR to be at that place where it really is.
Answer:
This could represent something like sliding a small rock across an icy lake.
Explanation:
A 20N force of gravity (weight), and 20N normal force exerted back onto the object imply it is on the ground and has no vertical motion. There is a net force of 0N
An 80N force to the left and a 5N force to the right create a net force of 75N to the left. This means that there is a force acting on the object that makes it accelerate to the left. 80N represents a push or pull force and 5N represents a relatively small frictional force due to the object being slid on a surface such as steel or in this case ice.
Answer:
Attention all people! There is a girl trying to get people to press this link and she tries to control your computer and steal your information that is on the computer! SHE WILL CAUSE A VIRUS!!!!! DO NOT PRESS ANY LINKS!!!!!!!!!
Explanation:
A. To solve for part A, we use the formula of Young’s
double slit equation:
x = λ L m / d<span>
</span>Where,
x = distance between adjacent dark lines or fringes =
12.5 cm = 0.125 m
λ = wavelength of light = 600 × 10^-9 m
L = distance from the two sources of light to
the screen = 1.2 m
m = number of fringes = 10 (tenth) – 1 (first)
= 9
d = separation of slits = unknown
Rearranging the equation in terms of d and
plugging in the values:
d = λ L m / x
d = (600 × 10^-9 m) (1.2 m) (9) / 0.125 m
d = 5.184 × 10^-5 m
d = 51.84 μm
B. The formula for path difference is:
path difference = (2 m + 1) (λ / 2)<span>
path difference = (2 * 9 + 1) (</span>600 × 10^-9 m / 2)
<span>path
difference = 5.7 × 10-6 m</span>
<span>path difference = 5.7 μm</span>