Answer:
Explanation:
Given
Initial Velocity (u)=13 m/s
angle
distance between fence and deer=2.5 m
We consider deer jump similar to projectile motion
equation of trajectory



Thus deer will cross the fence with an difference in its jump and fence
1.5-1.148=0.351 m



so deer rises during when it is over fence
- Displacement = 10 m
- Time = 5 s
- We know,

- Therefore, the car's velocity

<h3>Answer:</h3>
The car's velocity is 2 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
When conducting and experiment you want to have a notebook and something to write down notes with so you can keep everything organized and proper, and to not miss anything in the experiment. Also you want to have everything in order of the way it should be in.
I hope you found this helpful!
Answer: 25.7m/s
Explanation: the cars have equal masses so we only consider their velocities,
The cars traveled together at 65° north of east this is with a velocity equal to the resultant velocity,
Using the force diagram as shown below;
Tan 65° = Vn/Ve
Ve is velocity of the car traveling east
Vn is velocity of car traveling north
Tan 65° = V2/12
2.144 = V2/12
V2 = 12 * 2.144
V2 = 25.7 m/s
Answer:
With the equation:
sin T = l / a (*)
note that the width of the central diffraction maximum is inversely proportional to the width of the slit. If we increase the width size, a, the angle T at which the intensity first becomes zero decreases, resulting bin a narrower central band.
Explanation: