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FromTheMoon [43]
3 years ago
11

What is one piece of evidence that does NOT support the Big Bang Theory?​

Physics
1 answer:
svetoff [14.1K]3 years ago
3 0

Answer:

The redshift data does not support the Big Bang Theory and  without the redshift interpretation favored by the Big bang, there is  no Big Bang.  

Edwin Hubble did not believe that the redshift indicated  expansion. Hubble saw the redshift as an hitherto unrecognized  principle of nature.  The redshift is the effect of centripetal force mv2/r = mv2/ct =  v/c(mv/t) = v/c(p/t)= (v/c)m

The unrecognized principle of nature is the refraction effect of  gravity on light.  

n=c/v or v= c/n.

The Universe is older than 13.7 Billion years, likely around  16.5 billion years.  

The proper law of Gravity is W = -mGM/r + cmV = -mu/r + cP where  cP is the so-called "Dark Energy", or the actual vector Momentum  Energy cmV= cP. This is The Quaternion Universe with scalar and  vector energy!

Hope this helps!

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If you have 100 W expended over 20 s how much energy did it take?
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Energy = 2,000 watt-sec

<em>Energy = 2,000 J</em>

8 0
3 years ago
Which of these processes in the water cycle occur at a very high rate, to cause a hurricane?
Pavel [41]
Answer: d. evaporation and condensation

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5 0
3 years ago
A ride-sharing car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed
fgiga [73]

Answer:

Explanation:

Time taken to accelerate to 28 m /s

= 28 / 2 = 14 s

a ) Total length of time in motion

= 14 + 41 + 5

= 60 s .

b )

Distance covered while accelerating

s = ut + 1/2 at²

= 0 + .5 x 2 x 14²

= 196 m .

Distance covered while moving in uniform motion

= 28 x 41

= 1148 m

distance covered while decelerating

v = u - at

0 = 28 - a x 5

a = 5.6 m / s²

v² = u² - 2 a s

0 = 28² - 2 x 5.6 x s

s = 28² / 2 x 5.6

= 70 m .

Total distance covered

= 196 + 1148 + 70

= 1414 m

total time taken = 60 s

average velocity

= 1414 / 60

= 23.56 m /s .

8 0
3 years ago
An object with a mass m slides down a rough 370 inclined plane where the coefficient of kinetic friction is 0.20. If the plane i
Svetllana [295]

Answer:

v \approx 9.312\,\frac{m}{s}

Explanation:

The Free Body Diagram of the system is presented in the image attached below. The final speed is determined by means of the Principle of Energy Conservation and the Work-Energy Theorem:

K_{A} + U_{g,A} = K_{B} + U_{g,B} + W_{loss}

K_{B} = K_{A} + U_{g,A}-U_{g,B} - W_{loss}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot s\cdot \sin \theta - \mu_{k}\cdot m \cdot g \cdot s \cos \theta

\frac{1}{2}\cdot v^{2} = g\cdot s \cdot (\sin \theta - \mu_{k}\cdot \cos \theta)

v = \sqrt{2\cdot g \cdot s \cdot (\sin \theta - \mu_{k}\cdot \cos \theta)}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (10\,m)\cdot (\sin 37^{\textdegree} - 0.2\cdot \cos 37^{\textdegree})}

v \approx 9.312\,\frac{m}{s}

3 0
3 years ago
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