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g100num [7]
4 years ago
6

A 24 kg child descends a 5.0 m high slide and reaches the ground with a speed of 2.8 m/s. What is the mass of the child?

Physics
1 answer:
laila [671]4 years ago
7 0
The mass of the child in this problem is 24 Kg, the unit for mass is in Kilogram.
The mass will change only if it travels close to the speed of light.
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tigry1 [53]
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3 0
3 years ago
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A block of mass M on a horizontal surface is connected to the end of a massless spring of spring constant k. The block is pulled
slamgirl [31]

Answer:

Minimum coefficient of kinetic friction between the surface and the block is \mu_k=\frac{kx}{2Mg} .

Explanation:

Given:

Mass of the block = M

Spring constant = k

Distance pulled = x

According to the question:

<em>We have to find the minimum co-efficient of kinetic friction between the surface and the block that will prevent the block from returning to its equilibrium with non-zero speed.  </em>

So,

From the FBD we can say that:

⇒ Normal force, N=Mg                                   <em>...equation(i)</em>

⇒ Elastic potential energy, PE = \frac{kx^2}{2}               <em>  ...equation (ii)</em>

⇒ Frictional force, f = \mu_kN                                <em> ...equation (iii)</em>

⇒ Plugging (i) in (iii).

⇒ f=\mu_kMg

Now,

⇒ As we know that the energy lost due to friction is equivalent to PE .

⇒ PE=fx                     <em>...considering PE as</em> mgh or f(x) .

   Arranging the equation.

⇒ \frac{kx^2}{2}=\mu_k Mg (x)

⇒ \frac{kx}{2}=\mu_k Mg                 <em>...eliminating x from both sides.</em>

⇒ \frac{kx}{2Mg}=\mu_k                    <em>...dividing both sides wit Mg.</em>

Minimum coefficient of kinetic friction between the surface and the block is \frac{kx}{2Mg}=\mu_k .

4 0
4 years ago
What does the graph to the right represent?
Nastasia [14]
C the thermal equilibrium

4 0
4 years ago
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The uncertainty in the position of an electron along an x axis is given as 53 pm, which is about equal to the radius of a hydrog
Jobisdone [24]

To solve this problem it is necessary to apply the concepts related to the Heisenberg's uncertainty principle. Under this principle we understand the relationship that the minimum range of error in position (x) times the minimum range of error in momentum (p) is, at a minimum, about equal to the Planck constant, mathematically that is,

\Delta p = \frac{h}{\Delta x}

Replacing with our values we have,

\Delta p = \frac{6.63*10^{-34}J\cdot s}{2\pi (53*10^{-12}m)}

\Delta p = 1.99*10^{-24} kg\cdot m/s

Therefore the least uncertainty in any simultaneous measurement of the momentum component px of this electron is 1.99*10^{-24} kg\cdot m/s

4 0
3 years ago
More damage is done and more life is endangered in a head-on collision of two cars, each traveling at 30 mph, than in a
seropon [69]

Answer:

More damage is done and more life is endangered in a head-on collision of two cars, each traveling at 30 mph, than in a  car crashing into a brick wall at 30 mph because the relative velocities of the head-on collision are the sum of the two velocities.

Explanation:

Car crashing to a brick wall at 30 mph is less dangerous than two cars travelling in opposite direction at 30 mph each.

This is because, for one car, the other is at a relative speed of 30+30 = 60 mph.

6 0
4 years ago
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