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2 years ago

Which phase of matter does not change shape or volume? *

Chemistry

2 answers:

iris [78.8K]2 years ago

6 0

Answer:

SOLID

Three states of matter exist—solid, liquid, and gas. Solids have a definite shape and volume. Liquids have a definite volume, but take the shape of the container. Gases have no definite shape or volume.

Explanation:

RideAnS [48]2 years ago

3 0

Answer:

Solid is ur answer

Explanation:

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What is a covalent bond? Apex

AysviL [449]

Answer:

Here is the meaning of covalent bond: covalent bond: a chemical bond in which two atoms share some of their valence electrons which creates a force that holds the atoms together

Hope this helps

Sky

7 0

3 years ago

The sugar in your kitchen has a molar mass of 342.3 g/mol. How many particles are present inside a sugar bowl if there are 250 g

Anastaziya [24]

Number of particles inside a sugar bowl = 4.4 x 10²³

<h3>Further explanation</h3>

Given

The molar mass of sugar = 342.3 g/mol

mass of sugar = 250 g

Required

Number of particles

Solution

1 mol = 6.02 x 10²³ particles

mol of sugar :

$\tt mol=\dfrac{mass}{molar~mass}$

mol = 250 g : 342.3 g/mol = 0.73 mol

Number of particles :

N = n x No

N = 0.73 x 6.02 x 10²³

N = 4.39 x 10²³ ≈ 4.4 x 10²³

4 0

3 years ago

How many grams are there in 12.04 x 1024 molecules of H2O2?

Kruka [31]

Answer:

34.01468 grams

Explanation:

4 0

3 years ago

Rick is creating a love potion for Morty. To make the potion, Rick's needs 51 mL of a mixture solution where 40% is carbonated w

Deffense [45]

Answer:

The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL

Explanation:

So as to make the love potion, we have;

The percentage of carbonated water in the love portion = 40%

The percentage of green tea in the first solution = 65%

The percentage of carbonated water in the first solution = 15%

The percentage of whole milk in the first solution = 20%

The percentage of orange juice in the second solution = 17%

The percentage of lemonade in the second solution = 38%

The percentage of carbonated water in the second solution = 45%

Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;

x + y = 51...(1)

0.15·x + 0.45·y = 0.40×51 = 20.4

0.15·x + 0.45·y = 20.4...(2)

Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;

For equation (1)

y = 51 - x

For equation (2)

y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x

y = 136/3 - (1/3)·x

Equating the two equations of 'y', gives;

51 - x = 136/3 - (1/3)·x

51 - 136/3 = x - (1/3)·x

17/3 = (2/3)·x

(2/3)·x = 17/3

x = (3/2) × (17/3) = 17/2 = 8.5

x = 8.5

y = 51 - x = 42.5

y = 42.5

Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL

8 0

3 years ago

Propose a mechanism for the following reaction.

raketka [301]

First, recognize that this is an elimination reaction in which hydroxide must leave and a double bond must form in its place. It is likely an E2 reaction. Here is an efficient mechanism:
1) Pre-reaction: Protonate the -OH to make it a good leaving group, water. H2SO4 or any strong H+ donor works. The water is positively charged but still connected to the compound.
2) E2: Use a sterically hindered base, such as tert-butoxide (tButO-) to abstract the hydrogen from the secondary carbon. [You want a sterically hindered base because a strong, non-sterically hindered base could also abstract a hydrogen from one of the two methyl groups on the tertiary carbon, and that leads to unwanted products, which is not efficient]. As the proton of hydrogen is abstracted, water leaves at the same time, creating an intermediate tertiary carbocation, and the 2 electrons in the C-H bond immediately are used to make a double bond towards the partial positive charge.
In the products we see the major product and water, as expected. Even though you have an intermediate, remember that an E2 mechanism technically happens in one step after -OH protonation.

5 0

3 years ago