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Inessa [10]
3 years ago
14

A car is 200 m from a stop sign and traveling toward the sign at 40.0 m/s. At this time, the driver suddenly realizes that she m

ust stop the car. If it takes 0.200 s for the driver to apply the brakes, what must be the magnitude of the constant acceleration of the car after the brakes are applied so that the car will come to rest at the stop sign?
Physics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

The acceleration of the car will be a=9600m/sec^

Explanation:

We have given that distance from stop sign s = 200 m

Time t = 0.2 sec

We have to find the constant acceleration

Now from second equation of motion s=ut+\frac{1}{2}at^2

200=40\times 0.2+\frac{1}{2}\times a\times 0.2^2

a=9600m/sec^

So the acceleration of the car will be a=9600m/sec^

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E*2*π*r*L=λ*L/εo

E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C

6 0
3 years ago
Water that is moving across Earth’s surface is called
Vanyuwa [196]

Answer:

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5 0
2 years ago
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lapo4ka [179]

Answer:

24 Coulumbs

Explanation:

Given data

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I= √0.166

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We know also that

Q= It

substitute

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5 0
3 years ago
A lawyer drives from her​ home, located 88 milesmiles east and 1818 milesmiles north of the town​ courthouse, to her​ office, lo
myrzilka [38]

Answer:

the distance between the​ lawyer's home and her office is 124 miles

Explanation:

given information:

first lets assume that

x-axis (west = positive, east = negative)

y-axis (north = positive, south = negative)

thus,

distance of the house = (-88,18)

distance of the office = (13, -54)

thus, the distance between the​ lawyer's home and her office

R = √(x₂ - x₁)² + (y₂ - y₁)²

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7 0
3 years ago
50 POINTS
sweet-ann [11.9K]

Answer:

The acceleration is constant and positive

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The straight line indicates that the acceleration is constant, while the positive slope indicates that the line is positive.

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3 years ago
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