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AlladinOne [14]
3 years ago
15

Monochromatic light from a point source is directed toward the sharp edge of a solid object. How does diffraction change the ima

ge that appears on a screen beyond the object?
Why are diffraction patterns not commonly observed in everyday situations?
Physics
2 answers:
Anna71 [15]3 years ago
6 0

Did you get the answers the quiz??? If so please write out the answers in the comment section :)

Otrada [13]3 years ago
5 0

Monochromatic light from a point source is directed toward the sharp edge of a solid object.

  • A spot will be seen on the screen after diffraction.
  • The size of the obstructing object is greater than the wavelength of the incident light in everyday situations, so we are not able to view diffraction patterns in everyday situations.

<u>Explanation:</u>

When a monochromatic light from a point source is directed toward the sharp edge of a solid object, the light beam will get diffracted from the edge as the body of the solid object will not be passing the light. So the incident light will occur as a spots on the screen beyond the object after diffraction.

Diffraction of light occurs when the incident light falls on a grater and the width of the grater or the obstructing object should be comparable or lesser to the size of the wavelength. So, in everyday situations we do not observe diffraction patterns as the obstructing objects in real world.

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A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied
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We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that  the minimum force that must be applied on the <em>book is</em>

  • F=44N

From the question we are told

A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the  Force  is mathematically given as

F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\

F=44N

Therefore

the minimum force that must be applied on the <em>book is</em>

F=44N

For more information on this visit

brainly.com/question/23379286

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A 0.75 kg book is pushed across the table with an acceleration of 0.3 m/s2. What force is being applied to the
Brums [2.3K]

Answer:

\boxed {\boxed {\sf 0.225 \ Newtons}}

Explanation:

We are asked to find the force being applied to a book. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

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The mass of the book is 0.75 kilograms and the acceleration is 0.3 meters per square second. Substitute these values into the formula.

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F= 0.75 \ kg * 0.3 \ m/s^2

Multiply.

F =0.225 \ kg * m/s^2

1 kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 0.225 kilogram meters per second squared is equal to 0.225 Newtons.

F= 0.225  \ N

<u>0.225 Newtons of force</u> are applied to the book.

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Answer:

D

Explanation:

Option A, B and C are true about energy conversion devices, only option D is NOT true about energy conversion devices.

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