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vivado [14]
3 years ago
15

A Nichrome wire 44 cm long and 0.30 mm in diameter is connected to a 3.1 V flashlight battery. What is the electric field inside

the wire? (Enter the magnitude.)
Physics
1 answer:
Alexeev081 [22]3 years ago
4 0

Answer:

7.05 Volts/m

Explanation:

L = length of the Nichrome wire = 44 cm = 0.44 m

V = Potential difference across the end of the wire = battery voltage = 3.1 Volts

E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

E = \frac{V}{L}

Inserting the values

E = \frac{3.1}{0.44}

E = 7.05 Volts/m

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An object is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground. Calculate: a) The
frosja888 [35]

Answer:

0.41s

8.01m/s

Explanation:

Using the formula; v = u + at

Where;

u = initial velocity (m/s)

v = final velocity (m/s)

t = time (s)

a = acceleration (m/s²)

According to the provided information, u = 4m/s, s = 8m,

V = u + at

4 = 0 + 9.8t

4 = 9.8t

t = 0.41s

b) v = u + at

v = 4 + 9.8(0.41)

v = 4 + 4.018

v = 8.018m/s

8 0
3 years ago
In an elastic collision, two objects collide and return to their original positions with no loss of _________.
BARSIC [14]
No loss of kinetic energy! :)
6 0
4 years ago
In a double-slit experiment, if the central diffraction peak contains 13 interference fringes, how many fringes are contained wi
Ronch [10]

Answer:

Explanation:

Width of central diffraction peak is given by the following expression

Width of central diffraction peak= 2 λ D/ d₁

where d₁ is width of slit and D is screen distance and λ is wave length.

Width of other fringes become half , that is each of  secondary diffraction fringe is equal to

λ D/ d₁

Width of central interference  peak is given by the following expression

Width of  each of  bright fringe =  λ D/ d₂

where d₂ is width of slit and D is screen distance and λ is wave length.

Now given that the central diffraction peak contains 13 interference fringes

so ( 2 λ D/ d₁)  /  λ  D/ d₂ = 13

then (  λ D/ d₁)  /  λ  D/ d₂ = 13 / 2

= 6.5

no of fringes  contained within each secondary diffraction peak = 6.5

6 0
3 years ago
Which situation is the best example of translational motion?.
AleksAgata [21]

Answer:

 a block sliding down a ramp,a leaf blowing across a field

8 0
2 years ago
The volume of a gas is 605 liters at 27.0°C. The new temperature is -3.0°C. What is the new volume?
nlexa [21]
From p1v1/t1 = p2v2/t2
pressure unchanged ... cancelled out
v1=605 , t1=27C = 300K,
t2=-3C = 270K
***remember temperature must be in Kelvin
we got
605/300 = v2/270
v2 = 545
5 0
3 years ago
Read 2 more answers
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