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vivado [14]
2 years ago
15

A Nichrome wire 44 cm long and 0.30 mm in diameter is connected to a 3.1 V flashlight battery. What is the electric field inside

the wire? (Enter the magnitude.)
Physics
1 answer:
Alexeev081 [22]2 years ago
4 0

Answer:

7.05 Volts/m

Explanation:

L = length of the Nichrome wire = 44 cm = 0.44 m

V = Potential difference across the end of the wire = battery voltage = 3.1 Volts

E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

E = \frac{V}{L}

Inserting the values

E = \frac{3.1}{0.44}

E = 7.05 Volts/m

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Explanation:

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Answer:

(a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

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kx-mg=ma

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(b). If the compression is 2.5 times larger than it is when the mass sits in a still elevator,

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2.5\times\dfrac{mg}{k}=\dfrac{m}{k}(a+g)

a=2.5g-g

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(b). The acceleration is 1.5 g.

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