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MA_775_DIABLO [31]
3 years ago
11

A student dropped a pea size amount of K2CO3 into a solution of HCl(aq). He observed the formation of gas bubbles and collected

the gas into another test tube. The student performed a splint test and observed that the splint was extingished when he placed the splint into the test tube of the gas. What can be said about the results of this students experiment?
a. The student completed the experiment correctly and there were no errors in the experiment.
b. The experiment was performed incorrectly. K2CO3 doesn't react with HCl. Therefore, the student picked up the wrong compound when conducting the experiment.
c. The student performed the splint test incorrectly. He should of observed the splint flare up when the splint was placed in the test tube.
d. The student performed the splint test incorrectly. He should of observed a popping sound when the splint was placed in the test tube.
Chemistry
1 answer:
Wittaler [7]3 years ago
3 0

Answer:

The student completed the experiment correctly and there were no errors in the experiment.

Explanation:

When a pea size amount of K2CO3 is dropped into a solution of HCl, the following reaction occurs;

K2CO3(s) + 2HCl(aq) ----> 2KCl(aq) + CO2(g) + H2O(l)

The gas CO2 does not support burning hence, when the student performed a splint test and observed that the splint was extinguished when he placed the splint into the test tube of the gas.

Hence, the experiment was properly conducted and the student completed the experiment correctly and there were no errors in the experiment.

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Arisa [49]

False I hope this is right

8 0
3 years ago
Read 2 more answers
Ammonium carbonate decomposes upon heating according to
BaLLatris [955]

The total volume of the gas produced, given the data from the question is 11.84 L

<h3>How to determine the mole of (NH₄)₂CO₃</h3>
  • Mass of (NH₄)₂CO₃ = 11.83 g
  • Molar mass of (NH₄)₂CO₃ = 96 g/mol
  • Mole of (NH₄)₂CO₃ =?

Mole = mass / molar mass

Mole of (NH₄)₂CO₃ = 11.83 / 96

Mole of (NH₄)₂CO₃ = 0.123 mole

<h3>How to determine the volume of NH₃</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 2 moles of NH₃

Therefore,

0.123 mole of (NH₄)₂CO₃ will decompose to produce = 0.123 × 2 = 0.246 mole of NH₃

Thus, we can determine the volume of NH₃ produced by using the ideal gas equation as follow:

  • Temperature (T) = 22 °C = 22 + 273 = 295 K
  • Pressure (P) = 1.02 bar
  • Gas constant (R) = 0.08314 bar.L/Kmol
  • Number of mole (n) = 0.246 moles
  • Volume of NH₃ (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.246 × 0.08314 × 295) / 1.02

Volume of NH₃ = 5.92 L

<h3>How to determine the volume of CO₂</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of CO₂

Therefore,

0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of CO₂

Thus, we can determine the volume of CO₂ produced by using the ideal gas equation as follow:

  • Temperature (T) = 22 °C = 22 + 273 = 295 K
  • Pressure (P) = 1.02 bar
  • Gas constant (R) = 0.08314 bar.L/Kmol
  • Number of mole (n) = 0.123 moles
  • Volume of CO₂ (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.123 × 0.08314 × 295) / 1.02

Volume of CO₂ = 2.96 L

<h3>How to determine the volume of H₂O</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of H₂O

Therefore,

0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of H₂O

Thus, we can determine the volume of H₂O produced by using the ideal gas equation as follow:

  • Temperature (T) = 22 °C = 22 + 273 = 295 K
  • Pressure (P) = 1.02 bar
  • Gas constant (R) = 0.08314 bar.L/Kmol
  • Number of mole (n) = 0.123 moles
  • Volume of H₂O (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.123 × 0.08314 × 295) / 1.02

Volume of H₂O = 2.96 L

<h3>How to determine the total volume of gas produced</h3>
  • Volume of NH₃ = 5.92 L
  • Volume of CO₂ = 2.96 L
  • Volume of H₂O = 2.96 L
  • Total volume of gas =?

Total volume = 5.92 + 2.96 + 2.96

Total volume of gas = 11.84 L

Learn more about ideal gas equation:

brainly.com/question/4147359

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

7 0
2 years ago
The metallic radius of an aluminum atom is 143 pm. What is the volume of an aluminum atom in cubic meters?
Marina86 [1]

Answer:

6.61 × 10∧-29 m³

Explanation:

Given data:

Atomic radius= 143 pm = 143 × 10∧-12 m

volume = ?

Formula:

r = a/2√2

143 × 10∧-12 m = a/ 2√2

a= 143 × 10∧-12 m × 2√2

a= 404.4 × 10∧-12 m

where a is edge length, so we can calculate the volume by using following formula:

volume= a³

V= (404.4 × 10∧-12 m)³

v= 6.61 × 10∧-29 m³

8 0
4 years ago
The rate of disappearance of hbr in the gas phase reaction 2hbr(g)?h2(g)+br2(g) is 0.160 m s-1 at 150°c. the rate of appearance
luda_lava [24]
The reaction rates of the substances whether disappearance of a reactant or the appearance of a product are related to each other by the chemical reaction. The reaction rates are related as follows:

rate = rHBr / 2 = rBr2 = rH2

rH2 = 0.160 / 2 = 0.08 M/s
8 0
3 years ago
_Al2O3+heat=_Al+_O2​
Natalka [10]

Answer:

6.

2AI2O3 + heat ->  4AI + 3O2

Reaction type: Combustion

7.

2AI+ 6HCl -> 3H2 + 2AlCl3

Reaction type: Single Replacement

8.

IDK

Reaction type: Double Replacement?

Explanation:

8 0
3 years ago
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