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ch4aika [34]
3 years ago
12

i need help im a dum bleep who kept talking to guys on dc and one wont leave me alone what do i do (▰˘◡˘▰) (i already blocked hi

m he keeps making other acc)
Chemistry
1 answer:
Andrew [12]3 years ago
6 0

Answer:

Delete your discord acc, and make another one. Prob should change email tbh. If he keeps doing it you can report him, because it's like online stalking.

Explanation:

You might be interested in
Which statement is true about molecule speed? (1 point)
ANTONII [103]

Faster molecules have fewer collisions than slower molecules is True about molecular speed.

<h3>What is Molecular speed?</h3>

Molecular speed refers to the average distance gases or molecules travelled atca particular time rate.

It is valid in ideal gas, where the molecules do not interact with others.

Average molecular speed = Square root (3 (ideal gas constant) * (Temperature)/m)

Therefore, Faster molecules have fewer collisions than slower molecules is True about molecular speed.

Learn more about molecular speed from the link below.

brainly.com/question/14327643

8 0
2 years ago
What is the percent composition of dinotrogen pentoxide? With work shown please
iris [78.8K]

Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%

7 0
3 years ago
A student decomposed 3.67g of copper (ii) hydroxide into copper (ii) oxide. how many ml of 3m h2so4 is need to react with all th
vredina [299]
In the presence of heat, copper (II) hydroxide decomposes in to copper (II) oxide. 
Cu(OH)₂ (s) ----> CuO (s) + H₂O (l)
upon decomposition, water is removed from Cu(OH)₂
the amount of Cu(OH)₂ decomposed - 3.67 g
number of moles of Cu(OH)₂  - 3.67 g / 97.5 g/mol = 0.038 mol
stoichiometry of Cu(OH)₂ to CuO is 1:1
therefore number of CuO moles formed are - 0.038 mol
CuO reacts with sulfuric acid to form CuSO₄ 
CuO + H₂SO₄ ---> CuSO₄ + H₂O
stoichiometry of CuO to H₂SO₄ is 1:1
therefore number of H₂SO₄ moles that should react is 0.038 mol
the molarity of H₂SO₄ is 3M
this means that in 1000 ml - 3 mol of H₂SO₄ present 
so if 3 mol are present in 1000 ml 
then volume for 0.038 mol = 1000/3 * 0.038 
                                           = 12.67 ml
6 0
4 years ago
Vehicle emissions devices incorporate a chemical reaction to help control carbon monoxide pollution: 2CO+ O2-&gt;2CO2
BigorU [14]

<em>It convert carbon monoxide faster </em>

3 0
3 years ago
Read 2 more answers
Look at the diagram below.
Irina-Kira [14]

Answer:

if charge of ion is positive then it will loose electron

if charge of ion is negative it will gain electron

4 0
3 years ago
Read 2 more answers
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