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3 years ago

The earth's magnetic field is associated with the:

Physics

2 answers:

ladessa [460]3 years ago

7 0

I think is D. core

= 0 = )

ra1l [238]3 years ago

4 0

The earth's magnetic field is associated with the <span>core.</span>

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A car's velocity changes from 40 m/s to 30 m/s in 40 seconds. What is the

valina [46]

Answer:

- 0.25m/s²

Explanation:

Given parameters:

Initial velocity = 40m/s

Final velocity = 30m/s

Time taken = 40s

Unknown:

Acceleration of the car = ?

Solution:

Acceleration is the rate of change of velocity with time.

So;

Acceleration = $\frac{Final velocity - Initial velocity }{time }$

Acceleration = $\frac{30 - 40}{40}$ = - 0.25m/s²

This implies that the car will decelerate at a rate of 0.25m/s²

7 0

3 years ago

A student of weight 659 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude

Misha Larkins [42]

Answer:

a) The student feel light

b) Nbottom = 758 N

c) N'top= 236 N

d) N'bottom= 1055 N

Explanation:

a) W= 659N , Ntop= 560N

W > Ntop ---> Student feel less weight

b) Top:

∑F= W - Ntop = m.v²/R

m.v²/R = 659N - 560 N = 99 N

Bottom:

∑F= Nbottom- W = m.v²/R

Nbottom= W + m.v²/R = 659N + 99 N = 758N

c) W= 659 N , Ntop= 560 N , v'=2.v

N'top= ?

∑F= W - N'top = m.v'²/R

N'top= W - 4.m.v²/R

N'top = 659 N - 4. 99 N = 263 N

d) N'bottom = ?

∑Fbottom= N'bottom- W = m.v'²/R

N'bottom = W + 4.m.v²/R = 659 N + 4. 99 N = 1055 N

4 0

3 years ago

A proton moves with a speed of 1.17 105 m/s through Earth's magnetic field, which has a value of 50.0 µT at a particular locatio

vlabodo [156]

a) Southward you need to apply right hand rule. If you close your hand to the east, your thumb will indicate south.

b) Given the equation for Magnetic Force

$F= qVB$

Replacing

$F= (1.16*10^{-19})(1.17*10^5)(50*10^{-6})$

$F=9.36*10^{-19}$

c) Given the second Newton's Law by

$F_g = 1.67*10^{-27}*9.81$

$F_g = 1.64*10^{-26}$

Given the electric force by,

$F_e = 1.6*10^{-19}*1.5*10^2$

$F_e = 2.4*10^{-17}N$

$F=9.36*10^{-19}N$

7 0

3 years ago

A compound microscope is made with an objective lens (f0 = 0.900 cm) and an eyepiece (fe = 1.10 cm). The lenses are separated by

Marizza181 [45]

Answer:

-252.52

Explanation:

L = Distance between lenses = 10 cm

D = Near point = 25 cm

$f_o$ = Focal length of objective = 0.9 cm

$f_e$ = Focal length of eyepiece = 1.1 cm

Magnification of a compound microscope is given by

$m=-\frac{L}{f_o}\frac{D}{f_e}\\\Rightarrow m=-\frac{10}{0.9}\times \frac{25}{1.1}\\\Rightarrow m=-252.52$

The angular magnification of the compound microscope is -252.52

6 0

3 years ago

A car traveling at 5m/s starts to speed up after 3 seconds its velocity has increased to 11 m/s what is its acceleration

vfiekz [6]

Answer:

a=(v-u)/t

Explanation:

a =(11-5)/3

a= 8/3

a= 2.6 m/s

4 0

2 years ago