All categories

4 years ago

The earth's magnetic field is associated with the:

Physics

2 answers:

ladessa [460]4 years ago

7 0

I think is D. core

= 0 = )

ra1l [238]4 years ago

4 0

The earth's magnetic field is associated with the <span>core.</span>

You might be interested in

The only force acting on a 3.2 kg canister that is moving in an xy plane has a magnitude of 6.7 N. The canister initially has a

Fynjy0 [20]

Answer:

The work done by the force is 5.76 J

Explanation:

Given;

mass of canister , m = 3.2 kg

magnitude of force, f = 6.7 N

initial velocity of the canister on x-axis, $v_i$ = 3.3i m/s

final velocity of the canister on y- axis, $v_f$ = 6.9j m/s

The work done on the canister = change in the kinetic energy of the canister

$W = K.E_f - K.E_i$

where;

K.Ei is the initial kinetic energy

K.Ef is the final kinetic energy

The initial kinetic energy:

$K.E_i = \frac{1}{2} *m\sqrt{i^2 +j^2+z^2}\\\\K.E_i = \frac{1}{2} *3.2\sqrt{3.3^2 +0^2+0^2}\\\\K.E_i = 5.28 \ J$

The final kinetic energy:

$K.E_f = \frac{1}{2} *m\sqrt{i^2 +j^2+z^2}\\\\K.E_f = \frac{1}{2} *3.2\sqrt{0^2 +6.9^2+0^2}\\\\K.E_f = 11.04 \ J\\$

W = 11.04 - 5.28

W = 5.76 J

Therefore, work done on the canister by the 6.7 N force during this time is 5.76 J

3 0

3 years ago

There isnt enough sanitidzer(alcohol)what solution to be replaced

Alex Ar [27]

For me: WASH OUR HANDS REGULARLY

3 0

2 years ago

When a piece of metal mass of 72.17 g is

nordsb [41]

Answer:

Explanation:

The trick is in finding the volume.

Final Volume = 26.64

Initial Volume=<u>20.92</u> Subtract

Metal Volume 5.72 cm^3

Density = mass / volume

Density = 72.17 / 5.72

Density = 12.617

7 0

3 years ago

A jetliner rolls down the runway with constant acceleration from rest, it reaches its take off speed of 250 km/h in 1 min. What

nlexa [21]

Answer:

Acceleration, $a=14970.05\ km/h^2$

Explanation:

Given that,

Initially, the jetliner is at rest, u = 0

Final speed of the jetliner, v = 250 km/h

Time taken, t = 1 min = 0.0167 h

We need to find the acceleration of the jetliner. The mathematical expression for the acceleration is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{250}{0.0167}$

$a=14970.05\ km/h^2$

So, the acceleration of the jetliner is $14970.05\ km/h^2$ . Hence, this is the required solution.

3 0

3 years ago

8. Gravity pulls a skydiver down as air

sweet [91]

Answer:

Air resistance is pushing up on the parachute and force of gravity is pulling down so she slows down. This increases friction which slows free fall down. So when the skydiver reaches terminal velocity, the force of gravity is balance by air resistance. But when the forces are balance, there is no acceleration.

8 0

3 years ago