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Olin [163]
3 years ago
14

A 48-volt source is required to furnish 192 watts to a parallel circuit consisting of three resistors of equal value. What is th

e value of each resistor?
Physics
1 answer:
dem82 [27]3 years ago
4 0

Answer:

36 Ω

Explanation:

Since the 3 resistors are connected in parallel.

The combined resistance of the resistor is

1/Rc = 1/R + 1/R + 1/R ...................... Equation 1

Where Rc = combined resistance of the three resistor, R1 = Resistance of each of the resistor

Rc = R/3 ....................... Equation 2

The formula of power is given as

P = V²/Rc

Rc = V²/P ................ Equation 3

Where V = Voltage, R =  Combined Resistance, P = power.

Given: V = 48 V, 192 W.

Substitute into equation 3

Rc = 48²/192

Rc = 12 Ω

From equation 2

Rc = R/3

R = 3Rc

Where Rc = 12 Ω

R = 3×12

R = 36 Ω

Hence the resistance on each resistor = 36 Ω

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3 years ago
A block of ice at 0°C is added to a 150g aluminum calorimeter cup which holds 210 g of water at 12°C. If all but 2.0 g of ice me
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Answer:

original mass of the block of ice is 38.34 gram

Explanation:

Given data

cup mass = 150 g

ice temperature = 0°C

water mass = 210 g

water temperature = 12°C

ice melt = 2 gram

to find out

solution

we know here

specific heat of aluminum is c = 0.900 joule/gram °C

Specific heat of water C =  4.186 joule/gram °C

so here temperature difference is dt =  12- 0 = 12°C

so here heat lost by water and cup are given by

heat lost  = cup mass × c  × dt + water  mass × C × dt

heat lost  = 150 × 0.900  × 12 + 210 × 4.186 × 12

heat lost  = 12168.72 J

so

mass of ice melt here = heat lost / latent heat of fusion

here we know latent heat of fusion = 334.88 joule/gram

so

mass of ice melt  =  12168.72 / 334.88

mass of ice melt  is 36.337554 gram

so mass of ice is here = mass of ice melt + ice melt

mass of ice  =  36.337554 + 2

mass of ice  =  38.337554 gram

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3 years ago
Which two ways dose inertia affect the monitors of the planets
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Answer:

the inertia provides the tendency to maintain speed and keep moving

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2 years ago
The young tree was bent and has been brought into a vertical position by the three guy cables. If tension at AB = 0, AC = 10 lb,
KATRIN_1 [288]

Answer:

The young tree, originally bent, has been brought into the vertical position by adjusting the three guy-wire tensions to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Determine the force and moment reactions at the trunk base point O. Neglect the weight of the tree.

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Explanation:

See attached picture.

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4 years ago
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