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Marrrta [24]
3 years ago
15

Created from the ...... of ..... in layers over long periods of time

Chemistry
1 answer:
Setler79 [48]3 years ago
8 0
Sedimentary rocks. Not sure though
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A piece of rubber has a mass of 495 kg and a volume of 355 liters. Will it float in water, which has a density of 1.0 g/mL?
hoa [83]
Compare the density of the rubber to water. If it is less that 1 g/mL then it floats in the water.

You must compare density in the same units. So convert to g/mL 

( \frac{495kg}{355L} )*( \frac{1000g}{1kg} )*( \frac{1L}{1000mL} ) = 1.39 g/mL

The rubber does not float in water.
6 0
3 years ago
In an experiment Nyla collected the following information about a solution made from a certain food:
lorasvet [3.4K]

Answer:

D

Explanation:

pH<7

so it must be acid

easy ;)

4 0
3 years ago
If you have 120. mL of a 0.100 M TES buffer at pH 7.55 and you add 3.00 mL of 1.00 M HCl, what will be the new pH? (The pKa of T
Simora [160]

Answer:

The new pH after adding HCl is 7.07

Explanation:

The formula for calculating pH of a buffer is

pH = pKa + log([Conjugate base]/[Acid])

<u>Before adding HCl,</u>

         7.55 = 7.55 + log([Conjugate base]/[Acid])

⇔      log([Conjugate base]/[Acid])  = 0

⇔     [Conjugate base] = [Acid] = 1/2 x 0.100 = 0.05 M

⇒ Mole of Conjugate base = Mole of Acid = 0.05 M x 0.12 mL = 0.006 mol

<u>After adding HCl (3.00 mL, 1.00 M)</u>

⇒ Mole of HCl = 0.003 x 1 = 0.003 mol)

New volume solution is 120 m L+ 3 mL = 123 mL

HCl is a strong acid, it will convert the conjugate base to acid form, or we can express

Mole of new Conjugate base = 0.006 - 0.003 = 0.003 mol

                ⇒ Concentration = 0.003/0.123 M

Mole of new Acid form = 0.006 + 0.003 = 0.009 mol

                ⇒ Concentration = 0.009/0.123 M

Use the formula

pH = pKa + log([Conjugate base]/[Acid])

    = 7.55 + log(0.003 / 0.009) = 7.07

8 0
2 years ago
What is the pH of a solution with [H+]=6.2x10-9 M?
Serga [27]

Answer: 8.2

Explanation:

pH of a solution is  - Log [ H+].

pH = - Log [ 6.2 x 10-9 M]

     = 9 - 0.7924

pH =  8.24 approx 8.2

3 0
3 years ago
What is the one variable that is changed in the experimental group called? the placebo the independent variable the control grou
BlackZzzverrR [31]

Answer:

the independant variable

Explanation:

4 0
3 years ago
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