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3 years ago

During which stage of the cell cycle dies the cell condense chromosomes and break down the nuclear envelope

Chemistry

1 answer:

saveliy_v [14]3 years ago

5 0

Answer:

Prophase

Explanation:

During prophase, the chromosomes condense, the nucleolus disappears, and the nuclear envelope breaks down.

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PLSSS HELP FAST

Aliun [14]

Note the formula

$\boxed{\sf Mass\:no=No\:of\:protons+No\:of\:neutrons}$

For X:-

No of protons:-

$\\ \sf\longmapsto 19-10=9protons$

It is Fluorine.

For Y:-

No of protons:-

$\\ \sf\longmapsto 16-8=8protons$

It is Oxygen.

Option D is correct

7 0

2 years ago

Write a balanced chemical equation for the standard formation reaction of liquid acetic acid hch3co2.

Afina-wow [57]

The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,

$2C(gr) +2H_{2} (g) +O_{2} (g)$ → $CH_{3} COOH(l)$

The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.

$C(gr) +H_{2} (g) +O_{2} (g)$ → $CH_{3} COOH(l)$

The balanced chemical equation for the standard formation reaction of liquid acetic acid as,

$2C(gr) +2H_{2} (g) +O_{2} (g)$ → $CH_{3} COOH(l)$

The combustion of liquid acetic acid is given as,

$CH_{3} COOH(l) + 2O(g)$ → $2CO_{2}((g) +2H_{2} O(l)$ ΔH =-873

learn more about balancing chemical equation

brainly.com/question/15052184

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5 0

2 years ago

(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g

Schach [20]

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

5 0

3 years ago

why is it better to use several trials of a titration rather than one trial to determine the concentration of a solution of unkn

svlad2 [7]

Because you are never 100% precise during the work, so it's best and most accurate answer is always the average of more trials. basically the more you do, the more accurate the answer shall be

6 0

3 years ago

On a camping trip, Marta roasts a marshmallow in the campfire. The marshmallow grows, and then turns black.

Mandarinka [93]

Answer:

The answer is D.

Explanation:

4 0

3 years ago

Read 2 more answers