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BaLLatris [955]
2 years ago
15

During which stage of the cell cycle dies the cell condense chromosomes and break down the nuclear envelope

Chemistry
1 answer:
saveliy_v [14]2 years ago
5 0

Answer:

Prophase

Explanation:

During prophase, the chromosomes condense, the nucleolus disappears, and the nuclear envelope breaks down.

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inessss [21]

Answer:

6.

a. D

b. F

Explanation:

4 0
3 years ago
An atom has radius of 227 pm and crystallizes in a body-centered cubic unit cell. What is the volume of the unit cell
sdas [7]

We will see that the volume of the unit cell is 144,070,699.06 pm^3

<h3>How to get the volume of a body-centered cubic unit cell?</h3>

In a body-centered cubic unit cell, the side length of the cube is given as:

S = \frac{4}{\sqrt{3} } *R

Where R is the radius of the atom.

And the volume of a cube is the side length cubed, then we can see that the volume of our cube will be:

V = S^3 = (\frac{4}{\sqrt{3} }*227pm)^3

Solving that we get:

V  = (\frac{4}{\sqrt{3} }*227pm)^3 = 144,070,699.06pm^3

This is the approximated volume of the unit cell.

If you want to learn more about unit cell structures, you can read:

brainly.com/question/13110055

5 0
2 years ago
PLEASE HELP ME ITS DUE TODAY!!!
vova2212 [387]
D. The African Plate
5 0
3 years ago
Read 2 more answers
The empirical formula for a compound that is 1.2% h, 42.0%cl, and 56.8%o is
Charra [1.4K]
Hope you understand how to work out those types of questions now xD ;)

7 0
2 years ago
Determine a massa, em kg, de um material que está contida em um volume de 18L. Sabe-se que a densidade do material é de 0,9 g/cm
suter [353]
The question in English is "<span>Determine the mass, in kg, of a material that is contained in a volume of 18L. It is known that the material density is 0.9 g/cm 3"

Answer: 
</span>
We can use a simple equation to solve this problem. <span>
    d = m/v</span><span>

<span>Where </span>d <span>is the density, </span>m <span>is the mass and </span>v is the volume.

d = </span>0.9<span> g/cm³
m = ?
v = </span>18 L = 18 x 10³ cm³<span>

By applying the equation,
<span>    0.9 g/cm³ = m / </span></span>18 x 10³ cm³<span>
                  m = 0.9 g/cm³ x </span>18 x 10³ cm³<span> 
<span>                  </span>m = 16200 g
                  m = 16.2 kg

Hence, the mass of 18 L of material is 16.2 kg.</span>
6 0
2 years ago
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