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bezimeni [28]
3 years ago
14

Please help asap! Giving brainliest to correct answer!!

Chemistry
1 answer:
eduard3 years ago
3 0
The answer is d, because the simplest form of C4H10 is C2H5 which is the empirical formula
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(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g
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Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

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When a pendulum swings, if it is not continuously pushed it will not stop eventually because some of its energy is changed into.
Vladimir79 [104]
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Explain why it is important for cells to exchange materials.
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Explanation:

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3 years ago
Empirical formula of a compound is CH3. If the molar mass of the
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Answer:

Explanation:

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