Answer:
You may know the formula of calcium chloride (is:-CaCl2)
So.
CaCl2 ⇄ Ca-²+2Cl-¹
1mole⇄1mole+2moles
So from above ..
1mole CaCl2 produce 1mole Ca-² & 2 moles of Cl-².
For 2.5 moles we multiply the above chemical eq. With 2.5
2.5CaCl2⇄2.5Ca-²+5Cl-¹
So from 2.5 moles of CaCl2 we get 2.5 mole calcium ion and 5 moles chloride ion…
Explanation:
Answer:
Initial Velocity is when movement begins. When a body is at rest, the initial velocity is at 0 m/s.
Explanation:
Initial Velocity is the velocity at time interval t = 0
Answer:
0.00120 moles of electrons had traveled through the wire.
Explanation:
Amount current passed in 132 seconds = 0.880 A
Charge passed in 132 seconds = Q
![Q=0.88 A\times 132 s=116. C](https://tex.z-dn.net/?f=Q%3D0.88%20A%5Ctimes%20132%20s%3D116.%20C)
Number of electrons = N
Magnitude of charge on an electron = q = ![1.602\times 10^{-19} C](https://tex.z-dn.net/?f=1.602%5Ctimes%2010%5E%7B-19%7D%20C)
![Q=N\times q](https://tex.z-dn.net/?f=Q%3DN%5Ctimes%20q)
![N=\frac{116. C}{1.602\times 10^{-19} C}=7.25\times 10^{20}](https://tex.z-dn.net/?f=N%3D%5Cfrac%7B116.%20C%7D%7B1.602%5Ctimes%2010%5E%7B-19%7D%20C%7D%3D7.25%5Ctimes%2010%5E%7B20%7D%20)
1 mole =
ions/ particles/ atoms
The moles of electron in
electrons:
![=\frac{7.25\times 10^{20}}{6.022\times 10^{23}}=0.00120](https://tex.z-dn.net/?f=%3D%5Cfrac%7B7.25%5Ctimes%2010%5E%7B20%7D%7D%7B6.022%5Ctimes%2010%5E%7B23%7D%7D%3D0.00120)
0.00120 moles of electrons had traveled through the wire.
From the information given above, NAOH is a base and HNO3 is an acid.
The chemical equation for the reaction is as follows"
NAOH + HNO3 = NANO3 + H2O
From these equation, we can see that the mole ratio of acid to base is 1:1.
In the question, we are given the following information:
Concentration of the acid, CA = 0.20 M
Volume of the acid, VA = 15 ML
Concentration of the base, CB = 0.10 M
We are to calculate the volume of the base, VB = ?
The formula for calculating volume and concentration for acid and base is as follows:
CA * VA = CB * VB
VB = CA * VA / CB = 0.20 * 15 / 0.1 = 3.0 / 0.1 = 30
VB = 30 ML.
Therefore, the volume of base required to neutralize the acid is 30 ml.