It would be considered NEUTRAL
The moles of hydrogen required for the synthesis of 13.78 mol ethane has been 27.56 mol. Thus, option C is correct.
The balanced chemical equation for the synthesis of ethane has been:
![\rm C_2H_2\;+\;2\;H_2\;\rightarrow\;C_2H_6](https://tex.z-dn.net/?f=%5Crm%20C_2H_2%5C%3B%2B%5C%3B2%5C%3BH_2%5C%3B%5Crightarrow%5C%3BC_2H_6)
In a balanced chemical equation for the synthesis of 1 mole of ethane, 2 moles of hydrogen is required.
The moles of hydrogen required for the synthesis of 13.78 mol of ethane has been:
![\rm 1\;mol\;C_2H_6=2\;mol\;H_2\\13.78\;mol\;C_2H_6=13.78\;\times\;2\;mol\;H_2\\13.78\;mol\;C_2H_6=27.56\;mol\;H_2](https://tex.z-dn.net/?f=%5Crm%201%5C%3Bmol%5C%3BC_2H_6%3D2%5C%3Bmol%5C%3BH_2%5C%5C13.78%5C%3Bmol%5C%3BC_2H_6%3D13.78%5C%3B%5Ctimes%5C%3B2%5C%3Bmol%5C%3BH_2%5C%5C13.78%5C%3Bmol%5C%3BC_2H_6%3D27.56%5C%3Bmol%5C%3BH_2)
The moles of hydrogen required for the synthesis of 13.78 mol ethane has been 27.56 mol. Thus, option C is correct.
For more information about balanced equation, refer to the link:
brainly.com/question/7181548
Answer:
mettaliods
Explanation:
It has the both property of metal and non metal so it is called mettaliod.
Answer is: <span>percent ionization of aqueous acetic acid solution is 0.341%.
c(CH</span>₃COOH) = 1.55 M.
Ka(CH₃COOH) = 1.8·10⁻⁵.
Chemical reaction: CH₃COOH ⇄ CH₃COO⁻ + H⁺.
[CH₃COO⁻] = [H⁺] = x.
[CH₃COOH] = 1.55 M - x.
Ka = [CH₃COO⁻] · [H⁺] / [CH₃COOH].
1.8·10⁻⁵ = x² / (1.55 M - x).
Solve quadratic equation: x = 0.0053 M.
percent of ionization:
α = 0,0053 M ÷ 1.55 M · 100% = 0,341%
Answer:320kelvin
Explanation:
T Kelvin=t celcius +273
T Kelvin=47+273
T Kelvin=320
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