Question

You roll a fair 666-sided die. What is \text{P(roll less than 4})P(roll less than 4)start text, P, (, r, o, l, l, space, l, e, s, s, space, t, h, a, n, space, 4, end text, )? If necessary, round your answer to 222 decimal places

Answer 1

Answer:

Therefore,

Probability  for getting a number less than 4 is

$P(Roll\ Less\ than\ 4})=\dfrac{1}{2}$

Step-by-step explanation:

Given:

Let the Experiment be of rolling a 6 sided,

Let the sample space of the above experiment be S,

S = { 1, 2, 3, 4, 5, 6 }

n(S) = 6

Let A be the event of getting a number less than 4,

A = { 1 , 2, 3, }

n(A) = 3

Then the probability  for getting a number less than 4 is given by.

$P(A)=\dfrac{\textrm{Favorable Outcomes}}{\textrm{Total number of Favorable Outcomes}}=\dfrac{n(A)}{n(S)}$

Substituting the values we get

$P(A)=\dfrac{3}{6}=\dfrac{1}{2}$

Therefore,

Probability  for getting a number less than 4 is

$P(Roll\ Less\ than\ 4}=\dfrac{1}{2}$

Answer 2

Answer:3/6=1/2

Step-by-step explanation:

ecause all outcomes are equally weighted, the probability you are looking for is given by :-

Number of favorable eventsTotal number of events

Number of favorable eventsTotal number of events

In your case: 6 or Even outcome={2,4,6}6 or Even outcome={2,4,6} and Outcomes={1,2,3,4,5,6}Outcomes={1,2,3,4,5,6}

Hence:

Number of favourable eventsTotal number of events=36=12