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3 years ago

How can you maximize the use of useful materials that you have identified?

Chemistry

1 answer:

Bas_tet [7]3 years ago

8 0

Answer: The question is not complete, here is the complete question...

How can you maximize the use of useful materials that you have identified? empty bottles, fruits peeling,old news paper

The way to maximize the use of materials identified is by identifying the 3 R's of waste management which are Reduce, Recycle and reuse .

Explanation:

For example, when we check through the materialsempty bottles, fruits peeling,old news paper them can be Reduce, Recycle and reuse.

The plastic bottles can be recycled i.e converting the waste plastic materials into another useful materials like fabric, shoes, mats.

Fruits peeling can be reuse as composts for plants. These can be allow to be decompose which serve as plant compost to release nutrients for plants growth.

Old newspapers can be reduced by been sold to junks shop and some cash can be earned from it.

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3 years ago

A Sedentary lifestyle is a way of life that includes a lot of physical activity true or false?

geniusboy [140]

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2 years ago

How many particles of Na are there in 1.43g of a molecular compound with a Molar mass of 23g?

Olin [163]

Answer:

3.74 x 10²² particles

Explanation:

Given parameters:

Mass of compound = 1.43g

Molar mass of compound = 23g

Unknown:

Number of particles of sodium = ?

Solution:

To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;

Mass of sodium = $\frac{molar mass of Na}{molar mass of compound} x mass of sample$

= $\frac{23}{23} x 1.43g$

= 1.43g

Now find the number of moles of this amount of Na in the sample;

Number of moles = $\frac{mass}{molar mass}$ = $\frac{1.43}{23}$ = 0.062mole

Now;

1 mole of substance = 6.02 x 10²³ particles

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= 3.74 x 10²² particles

7 0

3 years ago

9.25 * 10^21 pennies if how many moles

Brrunno [24]

According to Avogadro constant 1 mole = 6.02 x 10^23 what about 9.25 x10 ^21

that is 1 mole x ( 9.25 x10 ^21) / (6.02 x10^23) = 0.0154 moles

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3 years ago

1. 50.0 g of an unknown metal was heated to 95.0 °C and added to 45.0 g of water at 25.0 °C

Soloha48 [4]

Answer

Q = mcΔT

Qwater = -Qmetal

(100 g)(4.18 J/g°C)(25°C - 20°C) = -(50 g)c(25°C - 90.0°C)

2090 J = (3250 g °C)c

c = 0.643 J/g °C

8 0

1 year ago

How can you maximize the use of useful materials that you have identified?​

How can you maximize the use of useful materials that you have identified?