Answer:
89°C
Explanation:
Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂
(1.25 atm)(450 mL)/(65°C) = (0.89 atm)(865 mL)/T₂
8.653846154 = 769.85/T₂
T₂ = 769.85/8.653846154
T₂ = 88.96044444 = 89°C
Answer:
Explanation:
Gold (111) Chloride:
AuCl₃
The oxidation state of gold is +3.
Chlorine is present in group seventeen and have seven valance electrons . Thus it accept one electron to complete the octet and show oxidation state -1.
When it react with gold(III) three chlorine atoms are combine with one gold atom to make compound overall neutral.
Calcium Carbonate:
CaCO₃
Carbonate formula is CO₃²⁻ . It means it carry -2 charge . Calcium is present in group two. It has two valance electrons and lose them to get complete octet thus shows +2 oxidation state.
When it combine with carbonate the overall compound is neutral because -2 and +2 charges cancel each other.
Hydrobromic Acid
HBr
Hydrogen has one electron while bromine has seven valance electrons. Bromine require one more electron to complete the octet. It react with hydrogen by sharing of one electron of hydrogen and form polar covalent compound.
Answer: pH of the solution is 12
Explanation:
NaOH —> Na+ + OH-
NaOH = 0.01M
Na+ = 0.01M
OH- = 0.01M
pOH = —log [OH-] = —log [0.01]
pOH = 2
pH + pOH = 14
pH = 14 — pOH = 14 — 2 = 12
pH = 12
Answer:
is the change in enthalpy associated with the combustion of 530 g of methane.
Explanation:
Mass of methane burnt = 530 g
Moles of methane burnt = 
Energy released on combustion of 1 mole of methane = -890.8 kJ/mol
Energy released on combustion of 33.125 moles of methane :
is the change in enthalpy associated with the combustion of 530 g of methane.
