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fiasKO [112]
3 years ago
13

how emissions, such as sulfur dioxide, nitrogen oxides or carbon dioxide from power plants contribute to the making of ozone?

Chemistry
1 answer:
Serga [27]3 years ago
8 0

Answer:

Explanation:

We cause air pollution directly through our use of electricity, fuels, and ... Most of this air pollution we cause results from the burning of fossil fuels, such as coal, oil, ... Carbon dioxide (CO2) is a good indicator of how much fossil fuel is burned ... with ozone-forming nitrogen oxides and volatile organic compound emissions.

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What is the name C2H4
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Ethylene, also named ethene.

Explanation:

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When magnesium hydroxide reacts with nitric acid, it produces magnesium nitrate and water. Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O
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The law of conservation of mass states that mass is neither created nor destroyed but the mass of the system must remain constant over time. The total number of atoms in the reactants is equal to the total number of atoms in the product. Therefore, this chemical equation shows that energy is conserved and demonstrates the law of conservation of mass.

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3 years ago
Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G
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<u>Answer:</u> The amount of silver produced in the given reaction is 459.63 g.

<u>Explanation:</u>

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of atoms.

For the given chemical equation:

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

By Stoichiometry of the reaction:

1 mole of copper produces 2 moles of silver.

This means that, 6.022\times 10^{23} number of atoms of copper produces 2\times 6.022\times 10^{23} number of atoms of silver.

So, 12.83\times 10^{23} number of atoms of copper will produce = \frac{2\times 6.022\times 10^{23}}\times 12.83\times 10^{23}=25.66\times 10^{23} number of atoms of silver.

We know that:

Mass of 1 mole of silver = 107.87 g

Using mole concept:

If, 6.022\times 10^{23} number of atoms occupies 107.87 grams of silver atom.

So, 25.66\times 10^{23} number of atoms will occupy = \frac{107.87g}{6.022\times 10^{23}}\times 25.66\times 10^{23}=459.63g

Hence, the amount of silver produced in the given reaction is 459.63 g.

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3 years ago
The atomic number is
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