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Talja [164]
3 years ago
6

Suppose you have a mixture of copper sulfate (CuSO4) and azulene (C10H8, you may wish to know the structure of azulene). Both co

pper sulfate and azulene are beautiful deep blue cystalline solids. If you transferred the mixture to a separatory funnel containing both an aqueous and and organic solvents (1M HCl and dichloromethane), into which layer would the copper sulfate partition, aqueous or organic?
A. Aqueous layer (1 M HCI)
B. Organic layer (dichloromethane)
C. Copper sulfate would partition nearly equally into both the aqueous and organic layers
Chemistry
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

Aqueous layer (1 M HCI)

Explanation:

First of us I want to remind you of the cliché in chemistry that like dissolves like. In solvent extraction, a mixture is dissolved in a system consisting of two immiscible solvents. One layer is organic while the other layer is aqueous.

Polar substances partition in the aqueous layer while nonpolar substances partition in the organic layer.

Since Copper sulfate is ionic, we will find it in the aqueous layer according to the old chemistry cliche.

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Which statement is true for a solution when its concentration of hydroxide ions increases? It becomes more acidic. It becomes le
makvit [3.9K]

Answer:

Its pH value increases.

Explanation:

pH is the measure of alkalinity or acidity of a compound.

pH = - log [H+]

and pH + pOH = 14

where pOH is the measure of basicity of a solution, given by -log[OH-]

As a solution gets more basic that is higher [OH-], the pH increases, and on the other hand, as the pH of a solution decreases by one pH unit, the concentration of H+ increases by ten times.

5 0
3 years ago
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Ground water has some minerals dissolved in it. If you heat this water, collect the vapor in another container, and then cool it
liq [111]
The answer would be the last one- it separates dissolved substances.

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6 0
3 years ago
What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?
Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>

m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.

<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>

<em>∴ The freezing point of the solution is - 4.39 °C.</em>

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After each half-life cycle, of the radioactive nuclei became nonradioactive.
kherson [118]

Answer:

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Explanation:

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Which element will react with cold water? (a) sodium (b)calcium (c)zinc (d)iron (e)copper (g)mercury
rjkz [21]

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