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Anni [7]
3 years ago
12

How do the two reflex arcs differ in complexity

Physics
1 answer:
DanielleElmas [232]3 years ago
3 0
<span>In a monosynaptic reflexes, it is like me speaking to you over a telephone. I am the only talker and you are the only listener. The phone line only has to connect to 2 people. If I am the one talking, I would be the sensory neuron, and if you are listening you would be the motor neuron. I can tell you what to do really fast because it is only 1 person I have to give instructions to. An example of this is the patellar reflex. The doc hits the patella and your leg kicks. This is becuse the sensory neuron gets hit and he quickly tells the motor neuron to kick. It happens really, really fast. Another example is touching a hot stove, what happens? Before you can even think to yourself that the stove is hot, your hand will pull away. Monosynaptic reflexes are made for very quick responses to stimuli that will not need to be stopped or thought about in order to react.



</span>
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3 years ago
What is the separation distance, in meters, between masses m1 = 15 x 107 kg and m2 = 62 x 107 kg when the gravitational force be
nalin [4]

Answer:

94.1 m

Explanation:

From Coulombs law,

F  = Gm1m2/r²................... Equation 1

where F = force, m1 = first mass, m2 = second mass, G = universal constant, r = distance of separation.

Make r the subject of the equation,

r = √(Gm1m2/F)................. Equation 2

Given: F = 7×10² N, m1 = 15×10⁷ kg, m2 = 62×10⁷ kg,

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute into equation 2

r = √( 6.67×10⁻¹¹×15×10⁷×62×10⁷/7×10²)

r √(886.16×10)

r √(88.616×10²)

r = 9.41×10

r = 94.1 m.

Hence the distance of separation = 94.1 m

3 0
4 years ago
The mass of a star is 1.61·1031 kg and its angular velocity is 1.60E-7 rad/s. Find its new angular velocity if the diameter sudd
Tcecarenko [31]

Answer:

ω₂ = 1.9025 x 10⁻⁶ rad/s

Explanation:

given,

mass of star = 1.61 x 10³¹ kg

angular velocity = 1.60 x 10⁻⁷ rad/s

diameter suddenly shrinks = 0.29 x present size

      r₂  = 0.29 r₁

using conservation of angular momentum

I₁ ω₁ = I₂ ω₂

(\dfrac{2}{5}mr_1^2)\omega_1=(\dfrac{2}{5}mr2^2)\omega_2

r_1^2\times \omega_1=r_2^2\times \omega_2

r_1^2\times 1.60\times 10^{-7}=(0.29r_1)^2\times \omega_2

1.60\times 10^{-7}=0.0841\times \omega_2

\omega_2=\dfrac{1.60\times 10^{-7}}{0.0841}

   ω₂ = 1.9025 x 10⁻⁶ rad/s

5 0
3 years ago
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