I believe the a is the correct answer is d
Answer:
mass P4 = 35.998 g
Explanation:
∴ STP: P = 1 atm; T = 298 K
∴ V O2= 35.5 L
⇒ nO2 = P.V / R.T
∴ R = 0.082 atm.L/K.mol
⇒ nO2 = ((1 atm)×(35.5L))/((0.082 atm.L/K.mol)(298K))
⇒ nO2 = 1.453 mol O2
⇒ mol P4 = (1.453 molO2)×(mol P4/ 5molO2) = 0.2906 mol P4
∴ Mw P4 = 123.895 g/mol
⇒ mass P4 = (0.2906 mol P4)×(123.895 g/mol) = 35.998 g P4
Answer:
Explanation:
Al (s) + CuSO4 (aq) → Cu (s) + Al2(SO4)3 (aq)
2Al (s) + 3CuSO4 (aq) → 3Cu (s) + Al2(SO4)3 (aq).
is the balance chemical equation
Answer:
21.2 gm
Explanation:
calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units
butane is the hydrocarbon C4H10
in combustion, we react hydrocarbons with O2 to form CO2 and H2O
so
C4H10 + O2----------------> CO2 + H2O
BALANCE
2C4H10 + 1302--------> 8CO2 + 10 H2O
the molar mass of CO2 is 12 + 16X2 = 44
64.1 gm of CO2 is
64.1/44 = 1.46 MOLES OF CO2,
FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE IT IS A
8:2 OR 4:1 RATIO. THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2
SO
THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES
THE MOLAR MASS OF BUTANE IS 58.12
0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm
0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .
<h3>What do mean by the term "gallons" ?</h3>
The gallon is a unit of measurement for volume and fluid capacity in both the US units and the British imperial systems of measurement.
In SI base units, 1 Gal is equal to 0.01 m/s²
Since ,
1 L, l = 0.2641720524 gal
now, volume of acid in gallons is given by -
2.3 L, l = 2.3 × 0.2641720524 gal
=0.60759572 gal
Hence , 0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .
Learn more about gallon ,here:
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