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4 years ago

100 POINTS ANSWER FAST

2 answers:

5 0

The answer is A because it has the most amount of speed, the plane has the same speed but doesn't tell you for what amount of time is the speed so what if the plane traveled 15 per 2 hours or 3 obviously the truck is going faster and it if said 15 miles per minute then it would obviously be the plane but since it doesn't specify then the truck would be you rmost likely answer

Hope this helps

LuckyWell [14K]4 years ago

5 0

The answer is A I am pretty sure

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Why is potassium sulfate K2SO4, but strontium sulfate SrSO4?

Oksi-84 [34.3K]

The sulphate ion has a charge of 2-, and potassium has a charge of 1+. To fully neutralise the charge on a sulphate ion, you need two potassium ions.

However, strontium has a charge of 2+. To neutralise the sulphate ion's 2- charge, one strontium ion is enough, so only one bonds to the sulphate.

Hope I helped! xx

7 0

3 years ago

Determine the empirical formulas for compounds with the following percent compositions:

White raven [17]

Answer: a) $CS_2$

b) $CH_2O$

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles$

Moles of S= $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.32}{1.32}=1$

For S = $\frac{2.63}{1.32}=2$

The ratio of C : S = 1:2

Hence the empirical formula is $CS_2$

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.7}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is $CH_2O$

5 0

3 years ago

What does the exosphere do??

vovikov84 [41]

In the case of bodies with substantial atmospheres, such as Earth's atmosphere, the exosphere<span> is the uppermost layer, where the atmosphere thins out and merges with interplanetary space. It is located directly above the thermosphere.</span>

7 0

4 years ago

Read 2 more answers

Points + Brainalist

Lorico [155]

Answer:

I think A it looks to be the answer

Explanation:

sorry if wrong

4 0

2 years ago

What will happen if Tajmahal will sink in sulphuric acid or in hydrochlorine acid?

adell [148]

Answer:

it will become yellowish in colour as it is made of marble ...

3 0

3 years ago