All categories

3 years ago

100 POINTS ANSWER FAST

2 answers:

5 0

The answer is A because it has the most amount of speed, the plane has the same speed but doesn't tell you for what amount of time is the speed so what if the plane traveled 15 per 2 hours or 3 obviously the truck is going faster and it if said 15 miles per minute then it would obviously be the plane but since it doesn't specify then the truck would be you rmost likely answer

Hope this helps

LuckyWell [14K]3 years ago

5 0

The answer is A I am pretty sure

You might be interested in

Chlorine has two naturally stable isotopes: 35Cl (34.968853 amu) and 37Cl (36.965903 amu). The natural abundance of each isotope

allochka39001 [22]

Answer:

35Cl ⇒ 34.968853 amu has an abundance of 30.05%

Explanation:

The molar mass of chlorine, (which is the average of all its naturally stable isotope masses), is 36.36575 amu.

There are 2 naturally stable isotopes, this means together they have an abundance of 100%

The isotopes are:

35Cl ⇒ 34.968853 amu has an abundance of X %

37Cl ⇒ 36.965903 amu has an abundance of Y %

X + Y = 100% OR X = 100% - Y

36.36575 = 34.968853X + 36.965903Y

36.36575 = 34.968853(1-Y) + 36.936.96590365903Y

36.36575 = 34.968853 -34.968853Y + 36.965903Y

1.396897 = 1.99705Y

Y = 0.699 = 69.95%

X = 100-69.9 = 30.05%

To control, we can plug in the following equation:

34.968853 * 0.3005 + 36.965903 * 0.6995 = 36.3658

This means

37Cl ⇒ 36.965903 amu has an abundance of 69.95 %

35Cl ⇒ 34.968853 amu has an abundance of 30.05%

7 0

3 years ago

Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:

posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of $HNO_3$ = $\frac{15.5g}{63g/mol\times 9.5L}=0.026M$

Equilibrium concentration of $NO$ = $\frac{16.6g}{30g/mol\times 9.5L}=0.058M$

Equilibrium concentration of $NO_2$ = $\frac{22.5g}{46g/mol\times 9.5L}=0.051M$

Equilibrium concentration of $H_2O$ = $\frac{189.0g}{18g/mol\times 9.5L}=1.10M$

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

For the given chemical reaction:

$2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)$

The expression for $K_c$ is written as:

$K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}$

$K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}$

$K_c=3.72$

Thus the value of the equilibrium constant Kc for this reaction is 3.72

5 0

3 years ago

All of the following can be recycled except

Lunna [17]

Compact fluorescent bulbs because they made out of glass that will break and will dye and then they can't be used again

7 0

4 years ago

How many g of silver chloride will be produced by reacting 10g of silver nitrate with sodium chloride?

I am Lyosha [343]

Answer:

16.8 g of AgCl are produced

Explanation:

The reactants are: NaCl and AgNO₃

The products are: AgCl, NaNO₃

Balanced equation: NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(s) ↓

We convert the mass of AgNO₃ to moles → 10 g / 85g/mol = 0.117 moles

Ratio is 1:1, therefore 0.117 moles of nitrate will produce 0.117 moles of AgCl.

According to stoichiormetry.

We convert the moles to mass → 0.117 mol . 143.3g /1mol = 16.8 g

7 0

3 years ago

Read 2 more answers

Calculate the amount (in grams) of kcl present in 75.0 ml of 2.10 m kcl

Lera25 [3.4K]

V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
---------------
C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
mKCl: 39+35.5 = 74,5 g/mol

74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl

:•)

5 0

3 years ago