<span>320. seconds
The ideal gas law is
PV = nRT
where
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = the ideal gas constant
T = absolute temperature of the gas.
Since we're going to want the volume, solve for V
PV = nRT
V = nRT/P
755 mmHg converts to 100658.11 Pascals
25 C = 298.15 K
Let's calculate nT/P, then we'll multiply by R
1 mol * 298.15 K / 100658.11 Pa = 0.002962007 K mol/Pa
The value for R in the most convenient units is 8.3144598 m^3 Pa/(K mol), so
0.002962007 K mol/Pa * 8.3144598 m^3 Pa/(K mol) = 0.024627486 m^3
So 1 mole of air at the specified temperature and pressure has a volume of 24.627 liters. The rest of the problem is now trivial. Just divide by the rate of consumption, so
24.627 l / 0.0770 l/s = 319.8374798 s
Rounding the result to 3 significant figures gives 320. seconds.</span>
At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.
<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
- At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
- However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
- u= initial velocity, θ= angle of projection
<h3>What's the acceleration of the ball at the highest point of projectile?</h3>
- During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
- But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.
Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
A- neither the ball's velocity nor its acceleration are zero.
B- the ball's acceleration points upward.
C- the ball's acceleration is zero but its velocity is not zero.
D- the ball's velocity points downward.
Learn more about the projectile motion here:
brainly.com/question/24216590
#SPJ1
Answer:
0.51
Explanation:
m = mass of the book = 3.5 kg
F = force applied by the broom on the book = 21 N
a = acceleration of the book
v₀ = initial speed of the book = 0 m/s
v = final speed of the book = 1.2 m/s
d = distance traveled = 0.74 m
Using the equation
v² = v₀² + 2 a d
1.2² = 0² + 2 a (0.74)
a = 0.973 m/s²
f = kinetic frictional force
Force equation for the motion of the book is given as
F - f = ma
21 - f = (3.5) (0.973)
f = 17.6 N
μ = Coefficient of kinetic friction
Kinetic frictional force is given as
f = μ mg
17.6 = μ (3.5 x 9.8)
μ = 0.51
<span>If
the amplitude is equal to 0.25m, then the distance travelled above and below
the equilibrium is also equals to 0.25m. it means if it starts above the
equilibrium, one period will be completed when it returns back to its original
position so, it travels 0.25 below, 0.25m back, 0.25m down and o.25 m when it
comes back to its original position, so the total distance we get is by adding
0.25m 4 times that is 1m.</span>
