Answer:
When truck is at rest while student is under motion
Explanation:
Since it is obvious that the mass of a truck is more than that of a student, we know that momentum is a product of mass and velocity
P=mv where m represent mass, v is velocity. When the student has more speed than that of truck, he exerts more momentum. The only way a student can exert more momentum is by having more speed while the truck is at rest. In such case, the momentum of truck will be zero while momentum of student will have a value
The correct answer to the question is : A) The velocity of the cart after it hits the wall.
EXPLANATION:
Before answering this question, first we have to understand impulse.
Impulse of a body is defined as the change in momentum or the product of force with time.
Mathematically impulse = m ( v- u ).
Here, v is the final momentum and u is the initial momentum.
Hence, we need the velocity of the cart after it hits the wall in order to calculate the impulse of the lab cart.
Answer:
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Answer:
Explanation:
Given
mass 
Force 
door knob is located at a distance of r=0.8 m from axis
Angular acceleration of door 
Torque 
where I=moment of inertia
