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2 years ago

8

a metal of length 15.04cm is heated until its temperature rises by 65°c. if its new length is 16.00m calculate its linear expans

ivity

1 answer:

spin [16.1K]2 years ago

5 0

Answer:

ΔL = L0 C ΔT

We need to find C the constant of expansivity

C = ΔL / (L0 ΔT)

C = .96 / (15.04 * 65) = 9.82 * 10^-4 / deg C

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A particle with a mass of 0.500 kg is attached to a horizontal spring with a force constant of 50.0 N/m. At the moment t = 0, th

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While the kinetic energy is given by:

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The velocity as a function of time t is:

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However, $\frac{m}{k}=\frac{1}{\omega^2}$ , so we have

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$0=A sin (\omega t)$

so, t=0.

When x=1.00 m, the equation of motion is:

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$T=\frac{2\pi}{\omega}=\frac{2\pi}{10 rad/s}=0.628 s$

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$T=2 \pi \sqrt{\frac{L}{g}}$

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Answer:

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